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There are 172 different arrangements.
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
Assuming you don't repeat letters:* 7 options for the first letter * 6 options for the second letter * 5 options for the third letter * 4 options for the fourth letter (Multiply all of the above together.)
Total arrangements are determined by the equation f(n) = n!, where n is the number of letters in the word, and n! is the factorial function, which is n*(n-1) ... *1. This word has 11! total arrangements. Distinguishable arrangements are determined by the equation f(n) = n!/(c1!*c2! ... *cn!), where the denominator is the product of the factorials of the count of each unique letter in the word. There is one "m". There are four "i"s. There are four "s"s. There are two "p"s. So: 11!/(4!4!2!1!) = 39916800/1152 = 34650 distinguishable arrangements
Quadrangle has four sides four angles and is ten letters long.
There are 172 different arrangements.
the arrangements occur. if there are two of the same letter then 12 all different letters then 24 three letters the same then 5 four letters the same then 1
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH = 7Number of letters to take= 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840
If the four letters "A" are to be together, "AAAA", then it's like having four differentletters; AAAA, L, B, M.The number of different arrangements (permutations) of the 7 letters in the word"ALABAMA" putting the four As together are;4! =4x3x2x1 =24
Aunt !
Assuming you don't repeat letters:* 7 options for the first letter * 6 options for the second letter * 5 options for the third letter * 4 options for the fourth letter (Multiply all of the above together.)
Precious stones are called gems.
Total arrangements are determined by the equation f(n) = n!, where n is the number of letters in the word, and n! is the factorial function, which is n*(n-1) ... *1. This word has 11! total arrangements. Distinguishable arrangements are determined by the equation f(n) = n!/(c1!*c2! ... *cn!), where the denominator is the product of the factorials of the count of each unique letter in the word. There is one "m". There are four "i"s. There are four "s"s. There are two "p"s. So: 11!/(4!4!2!1!) = 39916800/1152 = 34650 distinguishable arrangements
It is 1*5C3*(4*3*2*1) = 240
Yes, what is a word with four letters in it. Yes, "what" is a word with four letters in it.
Ohio, Iowa, Utah, and Iowa are four states that are only four letters long.