From a standard deck of playing cards, there are 52 cards. There are 13 cards for each Spades, Hearts, Clubs and Diamonds. For the first card, the probability of getting a Spade is 13/52.
If you're going to replace the first card into the deck, then the probability of second card being a Spade is also 13/52
Therefore, 13/52 x 13/52 = 1/16 (one in every sixteen tries)
If you're not going to replace the first card into the deck, the remaining deck will be left with a total of 51 cards and 12 Spades. Therefore the probability of second card being a Spade is 12/51
Lastly, 13/52 x 12/51 = 1/17 (one in every seventeen tries)
The answer depends on how many cards are drawn. If you draw 40 cards, the probability is 0. The probability of not drawing a spade in a random draw of one card from a standard deck is 39/52 = 3/4.
The probability of drawing a jack is 4 in 52. The probability of drawing a spade is 13 in 52. The probability of drawing a jack or a spade is 4 + 13 - 1 in 52, with the -1 compensating for one of the jacks also being a spade. 4 + 13 - 1 in 52 is 16 in 52, which is also 4 in 13, or about 0.3077.
One in four. There are 52 cards in the deck; 13 cards in each of four suits. Spades is one of the four suits, so you have one chance in 4 of picking a spade from a shuffled deck.
In order to determine the probability of drawing 2 hearts and then a spade, in that order, from a deck of 52 cards, start by considering the first card. The probability of drawing a heart is 1 in 4. Since you have now reduced the number of hearts and the number of cards in the deck by one, the probability of drawing another heart is 4 in 17. Since you have further reduced the number of cards by one, the probability of drawing a spade is 13 in 50. Multiply these probabilities together, (1/4) (4/17) (13/50), and you get about 0.0153, or about 153 in 10000.
Given the way you have worded the question I take it to mean, what is the probability of drawing at least one spade?We can do this most easily by asking first, what is the probability of drawing no spades on each of the 80 times. This is 39/52. The probability of doing this 80 times is (39/52)80.Then the probability of not doing this is 1 - (39/52)80, which is quite close to one. The probability of drawing at least one spade is almost one.
The answer depends on how many cards are drawn. If you draw 40 cards, the probability is 0. The probability of not drawing a spade in a random draw of one card from a standard deck is 39/52 = 3/4.
1/2
The probability of drawing a jack is 4 in 52. The probability of drawing a spade is 13 in 52. The probability of drawing a jack or a spade is 4 + 13 - 1 in 52, with the -1 compensating for one of the jacks also being a spade. 4 + 13 - 1 in 52 is 16 in 52, which is also 4 in 13, or about 0.3077.
The probability of drawing a spade or an ace from a 52 card deck of standard playing cards is 16 / 52 or approximately 30.8%. There are 13 spades in a standard deck of cards. There are four aces in a standard deck of cards. One of the aces is a spade. So, 13 + 4 - 1 = 16 spades or aces to choose from. Since we have a total of 52 cards, the probability of selecting an ace or a spade is 16 / 52 or approximately 30.8%.
One in four. There are 52 cards in the deck; 13 cards in each of four suits. Spades is one of the four suits, so you have one chance in 4 of picking a spade from a shuffled deck.
In order to determine the probability of drawing 2 hearts and then a spade, in that order, from a deck of 52 cards, start by considering the first card. The probability of drawing a heart is 1 in 4. Since you have now reduced the number of hearts and the number of cards in the deck by one, the probability of drawing another heart is 4 in 17. Since you have further reduced the number of cards by one, the probability of drawing a spade is 13 in 50. Multiply these probabilities together, (1/4) (4/17) (13/50), and you get about 0.0153, or about 153 in 10000.
Given the way you have worded the question I take it to mean, what is the probability of drawing at least one spade?We can do this most easily by asking first, what is the probability of drawing no spades on each of the 80 times. This is 39/52. The probability of doing this 80 times is (39/52)80.Then the probability of not doing this is 1 - (39/52)80, which is quite close to one. The probability of drawing at least one spade is almost one.
since there is only one Ace of Spades and 52 cards in a deck the probability would be 1/52.
In an ordinary deck of cards, there are 52 cards out of which 13 are spades. This means that the chances of drawing the first spade is 13 out of 52. The probability of the second spade is 12 out of 51 because one spade and, incidentally, one card are now missing. The third spade comes out as 11 out of 50 and the last one as 10 out of 49. Total probability of events that don't affect each other is the product of the individual probabilities. Thus, the chances of drawing four spades is (13 / 52) * (12 / 51) * (11 / 50) * (10 / 49), which is about 0.00264 -- in other words, one to 379.
A standard deck is 52 cards. These 52 cards are divided evenly into 4 suits - spades, clubs, diamonds, and hearts. There are 13 cards in each suit, ace through king. Therefore, there are 13 spades in a deck of 52 cards. 13 is one fourth of 52 which makes the probability of drawing a spade 1/4, .25, or 25 percent.
In a standard deck of 52 cards. Probability of drawing a spade: 4 suits, only 1 is spade. Each suit contains A-10 (10 cards) + K + Q + J (3 cards) 13 cards in each suit. There are 13 cards in the spades suit. You have a 13/52 chance of drawing a spade on your first draw. Probability of drawing a 5: there are only 4 5's in the deck. 3/52 chance of drawing a 5. (one 5card per suit that is not spades) 13/52 + 3/52 = 16/52 = .3076 or 30.8% chance of drawing a 5 or a spade on your first pull.
The probability of drawing a king given that you drew a spade or a club is 2 out of 26, or 1 out of 13. This is because there are 2 kings (one from spades and one from clubs) out of a total of 26 spade and club cards.