Assuming a two-sided coin, and that you make the the toss, the probability of tossing a head or a tail is 100%. The probability of tossing a head is 50%. The probability of tossing a tail is 50%.
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Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%
The probability is still 50%
In a single toss? zero. In two tosses, well that's a different question. Possible combinations are TT, HT, TH and HH, of which 2 of the 4 are one head and one tail. So probability is 0.50 in two tosses.
Expected number of heads is 1/4 * 32 or 8 heads.
If the sequence matters (you want H-H-T in that order), then . . .Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%=====================================================If the sequence doesn't matter, then the probability is higher.All the possible results of 3 tosses are:TTTTTHTHTTHHHTTHTHHHTHHHIf the sequence doesn't matter, there are 3 different ways to get 2 heads and 1 tail.The probability is3/8 = 0.375 = 37.5%