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On a fair 50-50 coin, the chance of you getting heads 3 times in a row is .5 * .5 * .5 which is 12.5%
Getting exactly 3 heads out of any number of coin flips involves:
(Number of Flips!/ [6 * (N-3)!]) * (.5^3)* (.5^(n-3))
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What is the probability of obtaining exactly seven heads in eight flips of a coin given that at least one is a head?
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
The probability of tossing three coins simultaneously and obtaining two heads and one tail is?
Looking at the total possibilities, you have eight different outcomes: TTT TTH THH HHH HHT HTT HTH THT Counting your two heads, one tails, you get a total of 3 possibilities out of 8, or 3/7
What is the probability of obtaining exactly four heads in five flips of a coin given that at least three are heads?
We can simplify the question by putting it this way: what is the probability that exactly one out of two coin flips is a head? Our options are HH, HT, TH, TT. Two of these four have exactly one head. So 2/4=.5 is the answer.
If a coin is tossed 3 times what is the probability of 3 heads?
There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.
What is the probability of obtaining exactly six heads in seven flips of a coin given that at least one is a head?
The requirement that one coin is a head is superfluous and does not matter. The simplified question is "what is the probability of obtaining exactly six heads in seven flips of a coin?"... There are 128 permutations (27) of seven coins, or seven flips of one coin. Of these, there are seven permutations where there are exactly six heads, i.e. where there is only one tail. The probability, then, of tossing six heads in seven coin tosses is 7 in 128, or 0.0546875.
What is the probability of obtaining three heads?
Probably 3/4
What is the probability of obtaining heads and a two?
The answer depends on what the experiment is!
What is the probability of obtaining 3 heads in three flips of a fair coin?
1/2 * 1/2 * 1/2 = 1/8 = 12.5%
What is the probability of obtaining exactly three heads in four flips of a coin given that at least one is a head?
50-50. each toss is independent of any previous toss. if all tosses are to be heads/tails then each toss you multiply by the number of chances. i,e. 2, starting with 1. three heads in a row is 1x2x2
What is the probability of obtaining exactly 4 heads in a coin?
About a 1 in 16 chance of getting a coin to land on heads 4 times in a row.
In an experiment, a biased coin is thrown ten times. If the probability of obtaining a head on any throw is 0.4 find the probability of obtaining?
Mr. Palmer moved to Canada in 1974 where he continued to teach and write. He died there on June 16, 2013. Related Documents.
What is the probability of obtaining exactly seven heads in eight flips of a coin given that at least one is a head?
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
What is the probability of obtaining exactly three heads in four flips of a coin given that at least two are heads?
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.
What is the probability of obtaining exactly 5 heads in 6 flips of a fair coin?
It is approx 0.0938
What is the probability of obtaining exactly two heads in three flips of a coin given that at least one is a head?
The probability of obtaining exactly two heads in three flips of a coin is 0.5x0.5x0.5 (for the probabilities) x3 (for the number of ways it could happen). This is 0.375. However, we are told that at least one is a head, so the probability that we got 3 tails was impossible. This probability is 0.53 or 0.125. To deduct this we need to divide the probability we have by 1-0.125 0.375/(1-0.125) = approximately 0.4286
What is the probability of obtaining exactly three heads in seven throws with a single coin?
(7!/(4!*3!))*(1/2)^3 * (1/2)^4 = 35*(1/2)^7 which is about 0.2734375
What is the probability of tossing a coin 6 times and obtaining at least 3 consecutive heads?
The probability is 5/16.
