Divide the number of possible even numbers by all the possible numbers. So there are three possible even numbers; 2, 4 & 6. And there are six possible numbers; 1, 2, 3, 4, 5, & 6. So the probability of throwing an even number is 3/6 = .5 .
The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.
On a fair normal die it is 1/2.
there's 1/3 chance of getting an even number in a die, hon
Assuming that there are an equal number of even and odd faces on the eight-sided die, then the probability of rolling an even number is simply 4 in 8, or 1 in 2, or 0.5.
Divide the number of possible even numbers by all the possible numbers. So there are three possible even numbers; 2, 4 & 6. And there are six possible numbers; 1, 2, 3, 4, 5, & 6. So the probability of throwing an even number is 3/6 = .5 .
On a fair die there is a equal chance of throwing any number.
The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.
On a fair normal die it is 1/2.
It is 0.01543
Probability of rolling an even number on a die is 1/2.
there's 1/3 chance of getting an even number in a die, hon
As there are an equal number of odd and even numbers on a single die, the odds of rolling an even number would be 50/50.
25%
probability of throwing a '6' on a single die: 1/6probability of throwing six on a pair of dice: 5/36
Assuming that the die is a regular 1 - 6 die, there is zero chance of you throwing an eight with a single six-sided die.
A standard die has no memory and so the probability of rolling an even number is always a half. If you did not know that the die was standard and were using the fact that 7 out of 12 rolls were even as an empirical estimate for a loaded die then the answer is 7/12.