for the data set shown below find the interwar range IQR. 300,280,245,290,268,288,270,292,279,282
43
Mean = Sum of values/Number of values = (46+35+...+43)/7 = 266/7 = 38 Median = Value in middle ie 4th position of ordered values = 37 Mode = Each of the seven values (some would say none). Range = Maximum - Minimum = 53 - 23 = 30
Mean: 40.17Median: 40Mode:noneRange: 1135, 37, 38, 42, 43, 46Mean is the average:(35 + 37 + 38 + 42 + 53 + 56)/6 = 241/6 = 40.17Median is the middle value in the list = 3rd & 4th values(38 +42)/2 = 80/2 =40Mode is thenumber that is repeated more often =noneRange is the largest value and the smallest value = 46 - 35 = 11
There is no actual "smallest" observation - a standard deviation of zero means that all 100 of the observations had to be 46.
Steps:1.) Arrange the data either ascending or descending order of their values.2.) Determine the total number of observations, say n.3.) If the set of number is odd then the middle number will be the median. And if the set of number is even then mean of middle two numbers will be the median.a.) After that we'll be starting to discuss and give examples on how to find the median of ungrouped data.Example1:1.) Find the median of 12, 15, 10, 18, 8.2.) Arrange the data either ascending or descending order of their values.8, 10, 12, 15, 18(ascending)18, 15, 12, 10, 8(descending)3.) If the set of numbers is an odd integer, find the middle number in the set of numbers.From the above middle number 12 then 12 is the median.Example2:1.) Find the median of 23, 46, 18, 32, 65, 20.2.) Arrange the data either ascending or descending order of their values.18, 20, 23, 32, 46, 65(ascending)65, 46, 32, 23, 20, 18(descending)3.) If the set of numbers is an even integer, find the two middle numbers in the set of numbers.From the above we can say that there are two middle numbers23 and 32. So,Md = 23+32/2 = 27.5By: HuebosFb: Jupete02@yahoo.comTwitter: @kimjupetehuebos
The range is 46.
46
It's 23 to 53 .
43/46 is in its simplest form.
88
The range is 8, since 50 ( largest number) minus 42 (smallest number) equals 8.
There isn't any.46 x 43 = 1978 . . . below the specified range47 x 43 = 2021 . . . above the specified range
This is a set of data. What do you want calculating?? You do not say. From it you can measure , MODE , MEDIAN, MEAN & RANGE.
Find the median of set of data 1 6 19 24 26 31 33 46
LCM(46, 43, 23) = 1978.
that's simple... the highest number: 99 minus the lowest number: 43 99-43=56
that's simple... the highest number: 99 minus the lowest number: 43 99-43=56