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120 is one standard deviation greater than the mean (z = 1).

So you want Pr(z < 1)

The probability of a score at most 1 sd away from the mean is 0.68

That is Pr(-1 < z < 1) = 0.68

So Pr(|z| > 1) = 1 - 0.68 = 0.32

then by symmetry,

Pr(z > 1) = 1/2*0.32 = 0.16

So Pr(z < 1) = 1 - 0.16 = 0.84

120 is one standard deviation greater than the mean (z = 1).

So you want Pr(z < 1)

The probability of a score at most 1 sd away from the mean is 0.68

That is Pr(-1 < z < 1) = 0.68

So Pr(|z| > 1) = 1 - 0.68 = 0.32

then by symmetry,

Pr(z > 1) = 1/2*0.32 = 0.16

So Pr(z < 1) = 1 - 0.16 = 0.84

120 is one standard deviation greater than the mean (z = 1).

So you want Pr(z < 1)

The probability of a score at most 1 sd away from the mean is 0.68

That is Pr(-1 < z < 1) = 0.68

So Pr(|z| > 1) = 1 - 0.68 = 0.32

then by symmetry,

Pr(z > 1) = 1/2*0.32 = 0.16

So Pr(z < 1) = 1 - 0.16 = 0.84

120 is one standard deviation greater than the mean (z = 1).

So you want Pr(z < 1)

The probability of a score at most 1 sd away from the mean is 0.68

That is Pr(-1 < z < 1) = 0.68

So Pr(|z| > 1) = 1 - 0.68 = 0.32

then by symmetry,

Pr(z > 1) = 1/2*0.32 = 0.16

So Pr(z < 1) = 1 - 0.16 = 0.84

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