12
For 8 9 9 9 10 11 11 12: σ=1.3562
It is 12.
There are 4 possible answers: (7, 7, 10, 13, 13) (7, 8, 10, 12, 13) (7, 9, 10, 11, 13) (8, 8, 10, 10 14).
That is not true. It is possible for a data set to have a coefficient of determination to be 0.5 and none of the points to lies on the regression line.
The variance is 10.
There are infinitely many sets. One possible set is {10,10,12,13,15}
The mode is the data set element(s) that is(are) repeated the most. If every data set element occurs the same number of times, there is no mode. As there is only one occurrence of each data set element in {11, 12, 13} there is no mode. If your data set read {11, 12, 12, 13, 13, 12} your mode would be 12. If your data set read {11, 12, 12, 13, 13} your modes would be 12 & 13.
26.66...
The variance of 2 3 5 12 = 20.3333
In order to find the weighted mean of this set of the data, we need to know the weight for each data in the set, and this information is not given in your question.Definition: When each number ai is to have weight wi, the weighted mean is equal to(w1a1+w2a2 + ... + wnan)/(w1 + w2 + ... + wn).
12
Compute the variance (or its square root , standard deviation) of each of the data set. Set 1: standard deviation = 10.121 Set 2: standard deviation = 12.09 Set 2 shows more variation around the mean. Check the link below
The variance of 29 21 12 19 19 = 37
The variance for 3 5 12 3 2 is: 16.5
the variance of the uniform distribution is (a+b)/12
For 8 9 9 9 10 11 11 12: σ=1.3562