If the distribution is Gaussian (or Normal) use z-scores. If it is Student's t, then use t-scores.
Z scores are used for standardized testing done by most school districts. It is the most common way of standardizing data. IQ scores can be standardized using z scores. The mean is 100 and the standard deviation is 15. You use the t score when the sample is small, <30 often. Many behavior ratings use t scores.
T-scores and z-scores measure the deviation from normal. The normal for T-score is 50 with standard deviation of 10. if the score on t-score is more than 50, it means that the person scored above normal (average), and vise versa. The normal for Z-score is 0. If Z-score is above 0, then it means that person scored above normal (average), and vise versa.
T scores are also standardized norm scores, where the mean value is 50 and standard deviation value is 10, in contrast to Z scores where mean value is "0" and standard deviation value is 1. -Rama Reddy Karri
z=(x-mean)/(standard deviation of population distribution/square root of sample size) T-score is for when you don't have pop. standard deviation and must use sample s.d. as a substitute. t=(x-mean)/(standard deviation of sampling distribution/square root of sample size)
You either look it up in a table of z scores or you can use a calculator such as the TI8 and use normalcdf.
T score is usually used when the sample size is below 30 and/or when the population standard deviation is unknown.
Z scores are used for standardized testing done by most school districts. It is the most common way of standardizing data. IQ scores can be standardized using z scores. The mean is 100 and the standard deviation is 15. You use the t score when the sample is small, <30 often. Many behavior ratings use t scores.
Best to use a histogram i think! z scores can probably be used too however they seem more a method of how to transform outliers in workable scores.
T-scores and z-scores measure the deviation from normal. The normal for T-score is 50 with standard deviation of 10. if the score on t-score is more than 50, it means that the person scored above normal (average), and vise versa. The normal for Z-score is 0. If Z-score is above 0, then it means that person scored above normal (average), and vise versa.
You calculate the z-scores and then use published tables.
T scores are also standardized norm scores, where the mean value is 50 and standard deviation value is 10, in contrast to Z scores where mean value is "0" and standard deviation value is 1. -Rama Reddy Karri
z=(x-mean)/(standard deviation of population distribution/square root of sample size) T-score is for when you don't have pop. standard deviation and must use sample s.d. as a substitute. t=(x-mean)/(standard deviation of sampling distribution/square root of sample size)
You either look it up in a table of z scores or you can use a calculator such as the TI8 and use normalcdf.
They should be.
True or False, One major advantage of transforming X values into z-scores is that the z-scores always form a normal distribution
3
zygote