There are nine possible successes:
1 - 5
5 - 1
2 - 4
4 - 2
3 - 3
3 - 6
6 - 3
4 - 5
5 - 4
The probability of success = 9/36 = 0.25 = 25%
Probability values are never negative and are always between 0-1 according to the definition Probability of A= Number of outcomes classified as A/Total number of possible outcomes
On a typical 6-sided number cube, there are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6). Therefore, there are three outcomes that are desired out of a total of six possible outcomes. 3/6 = 1/2, so your probability is 1 in 2 or 50%.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
1.00 or 100%. Look at the possible outcomes: 1, 2, 3, 4, 5, 6. In this range, what are the even numbers: 2, 4, 6. What are the odd: 1, 3, 5. So the set of (even or odd) numbers is the union of odd numbers and even numbers. This is the same as the set of possible outcomes. Therefore it will happen, so 100 percent chance (or 1.00)
The probability of an event is defined as the ratio of favourable outcomes to total outcomes. In the case of discrete distributions these will be represented by numbers, while for continuous distribution they will be measured as areas. In either case, the first measure is non-negative and the second is positive and so the probability is greater than 0. Also, the number of favourable outcomes cannot be greater than the total so the probability must be at most 1.
There is no single formula of probability. The probability of a simple event in a trial is a measure of all outcomes which result in the event, expressed as a proportion of all possible outcomes.If all the outcomes have the same probability then it is the ratio of the number of "favourable" outcomes to the total outcomes. However, the definition based on numbers fails if they are not equi-probable.
If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
Probability values are never negative and are always between 0-1 according to the definition Probability of A= Number of outcomes classified as A/Total number of possible outcomes
If the numbers (or symbols) are all different then 10 outcomes.
The probability of getting a multiple of 3 depends on the total number of possible outcomes. For example, if you are rolling a fair six-sided die, there are two outcomes that are multiples of 3 (3 and 6), out of a total of six possible outcomes. Therefore, the probability of getting a multiple of 3 is 2/6 or 1/3.
We assume the faces are marked with the numbers ' 1 ' through ' 8 '.Total number of possible outcomes = 8Number of successful outcomes = 3If the top is balanced, honest, and random, then . . .Probability of a successful outcome = (3/8) = 37.5 percent.Odds = 5 to 3 against it.
On a typical 6-sided number cube, there are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6). Therefore, there are three outcomes that are desired out of a total of six possible outcomes. 3/6 = 1/2, so your probability is 1 in 2 or 50%.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
When a Die is thrown then the probability of an event getting out-comes is not a prime number is 3/6. The possible prime numbers would be 2, 3, or 5. The possible outcomes are 1, 2,3,4,5 and 6. So 1,4 and 6 are not primes and there are 3 numbers out of 6 possible so that is 3/6 or p=.5
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
6 sides will be either 1,2,3,4,5, or 6 , so 6 possible outcomes