There are nine possible successes:
1 - 5
5 - 1
2 - 4
4 - 2
3 - 3
3 - 6
6 - 3
4 - 5
5 - 4
The probability of success = 9/36 = 0.25 = 25%
Probability values are never negative and are always between 0-1 according to the definition Probability of A= Number of outcomes classified as A/Total number of possible outcomes
On a typical 6-sided number cube, there are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6). Therefore, there are three outcomes that are desired out of a total of six possible outcomes. 3/6 = 1/2, so your probability is 1 in 2 or 50%.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
1.00 or 100%. Look at the possible outcomes: 1, 2, 3, 4, 5, 6. In this range, what are the even numbers: 2, 4, 6. What are the odd: 1, 3, 5. So the set of (even or odd) numbers is the union of odd numbers and even numbers. This is the same as the set of possible outcomes. Therefore it will happen, so 100 percent chance (or 1.00)
Divide the number of possible even numbers by all the possible numbers. So there are three possible even numbers; 2, 4 & 6. And there are six possible numbers; 1, 2, 3, 4, 5, & 6. So the probability of throwing an even number is 3/6 = .5 .
There is no single formula of probability. The probability of a simple event in a trial is a measure of all outcomes which result in the event, expressed as a proportion of all possible outcomes.If all the outcomes have the same probability then it is the ratio of the number of "favourable" outcomes to the total outcomes. However, the definition based on numbers fails if they are not equi-probable.
Probability values are never negative and are always between 0-1 according to the definition Probability of A= Number of outcomes classified as A/Total number of possible outcomes
If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
When rolling a standard six-sided number cube (die), the possible outcomes are the numbers 1, 2, 3, 4, 5, and 6. The numbers that fall between 2 and 5 are 3 and 4, which gives us 2 favorable outcomes. Since there are 6 possible outcomes in total, the probability of rolling a number between 2 and 5 is 2 out of 6, or simplified, 1/3.
If the numbers (or symbols) are all different then 10 outcomes.
The answer depends on the domain. If the selection is made from any real or rational numbers, the probability is 0. If the domain is all integers (or all positive integers) then the probability is 1/3. If it is some other subset of integers, then the answer is a rational number between 0 and 1/3.
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
We assume the faces are marked with the numbers ' 1 ' through ' 8 '.Total number of possible outcomes = 8Number of successful outcomes = 3If the top is balanced, honest, and random, then . . .Probability of a successful outcome = (3/8) = 37.5 percent.Odds = 5 to 3 against it.
When a Die is thrown then the probability of an event getting out-comes is not a prime number is 3/6. The possible prime numbers would be 2, 3, or 5. The possible outcomes are 1, 2,3,4,5 and 6. So 1,4 and 6 are not primes and there are 3 numbers out of 6 possible so that is 3/6 or p=.5
On a typical 6-sided number cube, there are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6). Therefore, there are three outcomes that are desired out of a total of six possible outcomes. 3/6 = 1/2, so your probability is 1 in 2 or 50%.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.