As the two events are independent multiply the respective probabilities together:
pr(5) = 1/6
pr(tails) = 1/2*
→ pr(5 and tails) = 1/6 × 1/2 = 1/12
*Actually it is slightly less than 1/2 as there is a very small probability that the coin will end up on its edge; for a small coin it is so small that it can be ignored, but with a scaled up coin it becomes a real possibility as (accidentally) demonstrated in the 1997 Royal Institution Christmas Lecture "The Magical Maze"
It is 3/4.
7-12
That's going to depend on how many numbered sides the "cube" has, and howthey're numbered.If it's literally a six-sided cube, with the faces numbered 1 through 6, then the onlymultiple of 4 anywhere on it is 4, and the probability of rolling the 4 is1/6 or (16 and 2/3) percent.
Sample space for rolling a number greater than 4 is {5,6} so 2 choices in total out of 6 P(>4)=2/6=1/3 is the answer
The probability is one in four, or 25%.
The probability is 1/42.
It is 3/4.
7-12
The probability of rolling doubles on a pair of dice is 1 in 6, or about 0.1667.
That's going to depend on how many numbered sides the "cube" has, and howthey're numbered.If it's literally a six-sided cube, with the faces numbered 1 through 6, then the onlymultiple of 4 anywhere on it is 4, and the probability of rolling the 4 is1/6 or (16 and 2/3) percent.
The probability of drawing the 10 is 1/10 and the probability of rolling a 3 is 1/6. So, the probability of both is 1/10 * 1/6 = 1/60.
Probability of coin heads up: 1/2 Rolling a 4 or 5 on the cube: 2/6 1/2 times 2/6 = 2/12, or 1/6.
Sample space for rolling a number greater than 4 is {5,6} so 2 choices in total out of 6 P(>4)=2/6=1/3 is the answer
A standard die has six faces numbered 1 through 6. The factors of 4 are 1, 2, and 4, so there are three favorable outcomes. Therefore, the probability of rolling a factor of four is the number of favorable outcomes (3) divided by the total number of outcomes (6), which is ( \frac{3}{6} ) or ( \frac{1}{2} ). Thus, the probability is 50%.
The probability is one in four, or 25%.
When rolling a standard six-sided die, the possible outcomes are the numbers 1 through 6. Out of these, only one number, 5, is divisible by 5. Therefore, the probability of rolling a number divisible by 5 is 1 out of 6, or approximately 16.67%.
In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.