As the two events are independent multiply the respective probabilities together:
pr(5) = 1/6
pr(tails) = 1/2*
→ pr(5 and tails) = 1/6 × 1/2 = 1/12
*Actually it is slightly less than 1/2 as there is a very small probability that the coin will end up on its edge; for a small coin it is so small that it can be ignored, but with a scaled up coin it becomes a real possibility as (accidentally) demonstrated in the 1997 Royal Institution Christmas Lecture "The Magical Maze"
It is 3/4.
7-12
That's going to depend on how many numbered sides the "cube" has, and howthey're numbered.If it's literally a six-sided cube, with the faces numbered 1 through 6, then the onlymultiple of 4 anywhere on it is 4, and the probability of rolling the 4 is1/6 or (16 and 2/3) percent.
Sample space for rolling a number greater than 4 is {5,6} so 2 choices in total out of 6 P(>4)=2/6=1/3 is the answer
The probability is one in four, or 25%.
The probability is 1/42.
It is 3/4.
7-12
The probability of rolling doubles on a pair of dice is 1 in 6, or about 0.1667.
That's going to depend on how many numbered sides the "cube" has, and howthey're numbered.If it's literally a six-sided cube, with the faces numbered 1 through 6, then the onlymultiple of 4 anywhere on it is 4, and the probability of rolling the 4 is1/6 or (16 and 2/3) percent.
The probability of drawing the 10 is 1/10 and the probability of rolling a 3 is 1/6. So, the probability of both is 1/10 * 1/6 = 1/60.
Probability of coin heads up: 1/2 Rolling a 4 or 5 on the cube: 2/6 1/2 times 2/6 = 2/12, or 1/6.
Sample space for rolling a number greater than 4 is {5,6} so 2 choices in total out of 6 P(>4)=2/6=1/3 is the answer
The probability is one in four, or 25%.
A die normally has 6 sides numbered 1 through 6. The probability of you landing on ANY number is 1:6, or you have a 1 in 6 chance of landing a 3.
The probability is 3/7.
The probability is 5/9.