In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
1/10
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
1/8 or .125 or 12.5%
3/16
17 out of 21
It is 0.5
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
9
The answer depends on how many sides the spinner has and how they are numbered. It also depends on how many time it is spun.
If it is a fair spinner, then 3/8
The probability is one in four, or 25%.
It depends on the number of numbers on the spinner and what those numbers are.
1/10
The probability is 5/9.
The probability is 3/7.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.