In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
1/10
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
To determine the probability of the spinner landing on an even number, you need to know the total number of sections on the spinner and how many of those sections contain even numbers. The probability is calculated by dividing the number of even-numbered sections by the total number of sections. For example, if the spinner has 8 sections numbered 1 through 8, there are 4 even numbers (2, 4, 6, 8), resulting in a probability of 4/8 or 1/2.
1/8 or .125 or 12.5%
17 out of 21
It is 0.5
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
9
The answer depends on how many sides the spinner has and how they are numbered. It also depends on how many time it is spun.
If it is a fair spinner, then 3/8
The probability is one in four, or 25%.
It depends on the number of numbers on the spinner and what those numbers are.
1/10
The probability is 5/9.
The probability is 3/7.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.