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(ax + b)^3 = a^3*x^3 + 3*a^2*x^2*b + 3*a*x*b^2 + b^3. Sorry, but it is so clumsy doing this without superscripts!
This is a binomial distribution; number of trials (n) is 6, probability of success (p) is 1/2 or 0.5. With this information you can go to a Binomial Distribution Table and find the solution. Within the section of values for n=6 and p=.5, read from the section the probability of 2 which is 0.2344 (see related link for table).
You use the Binomial distribution formula P(1 head out of 5 tosses) = 5C1 (1/2)^1 (1/2)^4 = 5 / 32
When the event of interest is a cumulative event. For example, to find the probability of getting three Heads in 8 tosses of a fair coin you would use the regular binomial distribution. But to find the probability of up to 3 Heads you would use the cumulative distribution. This is because Prob("up to 3") = Prob(0 or 1 or 2 or 3) = Prob(0) + Prob(1) + Prob(2) + Prob(3) since these are mutually exclusive.