None of the experimental probabilities need match the corresponding theoretical probabilities exactly.
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
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The probability of rolling a sum of 8 and doubles when rolling two dice is 1 in 36, or about 0.02778. Simply note that there are 36 permutations of two dice, of which exactly one of them (a 4 and a 4) matches the conditions specified.
For the sake of ease, I'm going to assume that you mean: if a family were to have four children, what is the probability of having two girls and two boys. (Note: if you actually mean a family of four, you would have to start building in the probability of single-parenthood and same-sex adoption since the parents would be included in the total family size.) One could do this problem the long way by writing out all combinations of children and identifying which one meets the criteria given in the problem and which ones do not. All Possible Combos of 4 Children GGGG BGGG GBGG GGBG GGGB BBGG BGBG BGGB GBGB GBBG GGBB GBBB BGBB BBGB BBBG BBBB Each set that matches our criteria are in bold. There are 6 "successful" pairings, out of a total of 16 possible combinations. Thus the probability is 6/16 or .375 or 37.5% that there will be two girls and two boys. That is a long way of doing this problem however and would not be as quick if we had asked about 10 children instead of only 4. Instead it is easier to think of this problem as the probability of one possible combination being correct then multiplying it by all the possible ways of writing it. You can take any possible combination of B and G as long as there are 2 Bs and 2 Gs. For this problem lets use: BBGG. The probability of this exact combination occurring is 1/16: (1/2) * (1/2) * (1/2) * (1/2) = 1/16 Remember that the probability of a certain series of independent events is equal to the each probability multiplied together. Now we must figure out all the possible ways of writing BBGG. In this case there are 6. So now 6 * (1/6) = 6/16 or 3/8 or .375 or 37.5%
3 + 3 + 3 + 3 + 3 = 15 total possible outcomes. You can 'prove' this by laying out a table of possibles where a user might tick the result of each game..... Match....1....2....3....4....5 Win......._...._...._...._...._ Lose......_...._...._...._...._ Draw....._...._...._...._...._
The probability that the second coin matches the first is 0.5 .The probability that the third coin matches the first is 0.5 .The probability that the second and third coins both match the first is (0.5 x 0.5) = 0.25 = 25%
the probability that the school team wins their next hockey match is 0.8. what is the probability that in their next 2 matches the school team a) wins both matches? b) wins neither match? thats wat i wanna know
Experimental data is an important component of any scientific paper.After looking at the data, we can compare that to our hypothesis and see if it matches to our tentative idea.Analysis of experimental data also helps us to draw a conclusion of an experiment.
The difference between the experimental value and the accepted value is known as the experimental error. It helps to quantify how closely the experimental result matches the true value.
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
Physics is known as an experimental science because it relies on making observations and performing experiments to verify theories and understand the natural world. Experimental evidence is crucial in validating or invalidating physical theories, allowing for the advancement of our understanding of the laws that govern the universe.
The theory of an expanding universe, known as the Big Bang theory, best matches the experimental evidence found by astronomers and physicists. Evidence such as the cosmic microwave background radiation and the redshift of distant galaxies support the idea that the universe began as a singularity and has been expanding ever since.
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Probability is used in these mediums to predict outcomes of events such as elections, sports matches, or economic trends. This helps in creating engaging content and informing the audience about potential future scenarios. Additionally, probability can be used to evaluate the credibility of sources and stories presented in the news.
If a theory does not agree with experimental results, you can either revise the theory to account for the discrepancies or discard the theory and develop a new one that aligns with the experimental evidence.
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The probability of rolling a sum of 8 and doubles when rolling two dice is 1 in 36, or about 0.02778. Simply note that there are 36 permutations of two dice, of which exactly one of them (a 4 and a 4) matches the conditions specified.