There are 12 months to choose from There are 7 months with 31 days in them.
The probability of choosing a 31-day month is 7/12.
First we don't consider leap year There is 1 month with 28 days: february There are 4 months with 30 days: april, june, september, november So the probability to select a month with 28 or 30 days is (1+4)/12 = 5/12 If the year is a leap year then the probability is 4/12
It is 1. Every month contains 28 days.
Absolute certainty
Let us assume that there are exactly 365 days in a year and that birthdays are uniformly randomly distributed across those days. First, what is the probability that 2 randomly selected people have different birthdays? The second person's birthday can be any day except the first person's, so the probability is 364/365. What is the probability that 3 people will all have different birthdays? We already know that there is a 364/365 chance that the first two will have different birthdays. The third person must have a birthday that is different from the first two: the probability of this happening is 363/365. We need to multiply the probabilities since the events are independent; the answer for 3 people is thus 364/365 × 363/365. You should now be able to solve it for 4 people.
The simplistic answer is that August will have five Mondays if the month starts on a Saturday, Sunday or Monday. Three days out of the seven so the probability is 3/7 = 0.4286. However, that assumes that any day of the week is equally likely and that is not the case. The impact of leap years and their 2800-year cycle is to increase the probability to 0.43
First we don't consider leap year There is 1 month with 28 days: february There are 4 months with 30 days: april, june, september, november So the probability to select a month with 28 or 30 days is (1+4)/12 = 5/12 If the year is a leap year then the probability is 4/12
The probability is 7:12... There are five months with less than 31 days, so the probability of selecting a month with exactly 31 days is 7 out of 12.
there are 4 monthes that has 30 days each year there are 12 monthes each year. so the probabillity for picking a month that has 30 days in it is 4/12
It is 1. Every month contains 28 days.
It is 7/12.
The probability is approx 15/16.
Absolute certainty
you wont get your birthday every year
Just over 7 out of 12.
Let us assume that there are exactly 365 days in a year and that birthdays are uniformly randomly distributed across those days. First, what is the probability that 2 randomly selected people have different birthdays? The second person's birthday can be any day except the first person's, so the probability is 364/365. What is the probability that 3 people will all have different birthdays? We already know that there is a 364/365 chance that the first two will have different birthdays. The third person must have a birthday that is different from the first two: the probability of this happening is 363/365. We need to multiply the probabilities since the events are independent; the answer for 3 people is thus 364/365 × 363/365. You should now be able to solve it for 4 people.
It depends what you mean by randomly. If its not eaten anything for one or two days - but regains its appetite, I wouldn't worry. However - if it's been more than a couple of days - take it to a vet for a check up !
The probability of randomly meeting someone born on a Monday is approximately 1 in 7, or about 14.3%. This is based on the assumption that births are evenly distributed across the days of the week. However, actual birth rates can vary slightly by day, influenced by factors such as hospital practices and cultural trends. Nonetheless, for a rough estimate, 1 in 7 is a reasonable approximation.