If these are meant to be the difference of two absolute quantities, the answer is zero.
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Equation 1: L+D=(8x60) L+D=480
D=480-L
Equation 2:
D=L+((4x60)+40)
D=L+(280)
480-L=L+280
-280 -280
200-L=L
+L +L
2000=2L
----- ------
2 2
100=L
D=480-L
D=480-100
D=380
it takes L 100 minutes and D 380 minutes
it takes L 1hr 40min and D 6 hr 20 min.
1 answer
Last Playoff Appearances:
AFC
East:
New England Patriots: 2009 Wild Card (L)
Miami Dolphins: 2008 Wild Card (L
Buffalo Bills: 1999 Wild Card (L)
New York Jets: 2009 Conference Championship (L)
North
Baltimore Ravens: 2009 Division (L)
Pittsburgh Steelers: 2008 Super Bowl XLIII (W)
Cleveland Browns: 2002 Wild Card (L)
Cincinnati Bengals: 2009 Wild Card (L)
South
Indianapolis Colts: 2009 Super Bowl XLIV (L)
Tennessee Titans: 2008 Division (L)
Houston Texans: 1st season 2002; Houston has never qualified for post season play
Jacksonville Jaguars: 2007 Division (L)
West
San Diego Chargers: 2009 Division (L)
Kansas City Chiefs: 2006 Wild Card (L
Denver Broncos: 2005 Conference Championship (L)
Oakland Raiders: 2002 Super Bowl XXXVII (L)
NFC
East
New York Giants: 2008 Division (L)
Dallas Cowboys: 2009 Division (L)
Washington Redskins: 2007 Wild Card (L)
Philadelphia Eagles: 2009 Wild Card (L)
North
Minnesota Vikings: 2009 Conference Championship (L)
Detroit Lions: 1999 Wild Card (L)
Chicago Bears: 2006 Super Bowl XLI (L)
Green Bay Packers: 2009 Wild Card (L)
South
Tampa Bay Buccaneers: 2007 Wild Card (L)
Atlanta Falcons: 2008 Wild Card (L)
Carolina Panthers: 2008 Division (L)
New Orleans Saints: 2009 Super Bowl XLIV (W)
West
San Francisco 49ers: 2002 Division (L)
Seattle Seahawks: 2007 Division (L)
St. Louis Rams: 2004 Division (L)
Arizona Cardinals: 2009 Division (L)
1 answer
internal thoracic R/L, subclavian R/L, brachiocephalic R/L, external jugular R/L, internal jugular R/L, axilary R/L
5 answers
L = 14 and W = 2 would give an area (A) of 28, or 7 (L) x 4 (W) = 28 (A)
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if your mean normal value, it is given below.
Serum Bilirubin 0.2-1.0mg/dl
SGOT <40u/l
SGPT <40u/l
Alkline Phosphatase 80-290 u/l
S.GGT 9-52 (M) iu/l
9-32(F) iu/l
1 answer
If you are referring to the shape of the cross section then it is commonly referred to as "L channel"
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How will L-Lysine help shingles or can it help==Have two folks have had great success with it..o How will L-Lysine help shingles or can it help==Have two folks have had great success with it..o
1 answer
1. L + W = P/2 = 300 so L = 300 - W;
2. L = 3W + 2 so 300 - W = 3W + 2 ie 4W = 298 making W = 74.5 and L 225.5
1 answer
L's name was written in Rem's notebook and Light's name was written in Ryuk's
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no not really LOLI (laughing out loud inside) LOL
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Lines are parallel if they are perpendicular to the same line. Since the lines m and l are parallel (given), and the line l is perpendicular to the line p (given), then the lines m and p are perpendicular (the conclusion).
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1 answer
On the 4.2 L - V6 engine , # 4 cylinder is on the drivers side , the front cylinder On the 4.6 L and 5.4 L V8 , # 4 cylinder is on the passenger side , the rear cylinder
1 answer
The letters LOL is an abbreviation of the phrase, laugh out loud. It is mostly used in text messages and in online chat tools or forums.
1 answer
1 L = 1000 cm3
_____________________________
1 L = 1000 cubic cm
1 cubic meter = 1000000 cubic cm
so, 1 L = one thousandth of cubic meter = 10-3 cubic meter
1 answer
L = 2N AND L + 4 = N + 6 SO L=4 AND N=2
Linda is 4.
1 answer
#include<stdio.h>
#include<string.h>
int max(int a,int b)
{
return a>b?a:b;
}//end max()
int main()
{
char a[]="xyxxzxyzxy";
char b[]="zxzyyzxxyxxz";
int n = strlen(a);
int m = strlen(b);
int i,j;
for(i=n;i>=1;i--)
a[i] = a[i-1];
for(i=m;i>=1;i--)
b[i] = b[i-1];
int l[n+1][m+1];
printf("\n\t");
for(i=0;i<=n;i++)
{
for(j=0;j<=m;j++)
{
if(i==0 j==0)
l[i][j]=0;
else if(a[i] == b[j] )
l[i][j] = l[i-1][j-1] + 1;
else
l[i][j] = max(l[i][j-1],l[i-1][j]);
printf("%d |",l[i][j]);
}
printf("\n\t");
}
printf("Length of Longest Common Subsequence = %d\n",l[n][m]);
return 0;
}
1 answer