1. L + W = P/2 = 300 so L = 300 - W;
2. L = 3W + 2 so 300 - W = 3W + 2 ie 4W = 298 making W = 74.5 and L 225.5
It is a polygon, whose area is 64. If the length is "x" and the height is "y" and it is a square, then the area is x times y is 64. If it is not a square, then the formulas get a bit more complicated, but the concept is the same. That is all true, but the question asks for a length. If you mean perimeter, that depends entirely on the shape of the polygon. If it is a square, and x and y are as above, then x equals y equals 8 meters, and the perimeter is 8 times 4 or 32 meters. If it is a rectangle, the perimeter will be at least 32 meters but there is no limit to how high the perimeter can be. For example, if x is 1 millimeter, then y has to be 64,000 meters or 64 kilometers, and the perimeter is 128,000.002 meters.
The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
The perimeter of a shape depends on its specific dimensions and type. If you are referring to a square with a side length of 18 inches, the perimeter would be calculated as 4 times the side length, resulting in 72 inches. For a rectangle, you would need both the length and width to calculate the perimeter. Please specify the shape for a more accurate answer.
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
Width = 10cm.. i think Length = 68cm
Length + width = half of perimeter, so you need more information...
The answer is centimetersImproved Answer:-The length works out as 9 and 1/3 cm
Width = 9 inches Length = 30 inches
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
18.4cm by 22.4cm
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
12 meters