V=1/3*pi*(R12+R1*R2+R22)*h
V = volume
pi = 3.142
R1 = Radius of the base
R2 = Radius of the top
h = height of the truncated cone
by my algebra, same as:
V=1/2*pi*(R12+R22)*h
The alternative algebra is not correct. Using the same positive values for R1 and R2 and the answers are not equivalent. The formula at the top matches Wikpedia and other sources on the web.
A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.
The formula for calculating development surface area of a truncated cone is Avr = π [s (R + r) + R^2 + r^2]. The solution is area (A) subscript r where r is the radius of the top of the truncated cone. In this formula R stands for the radius of the bottom of the cone and s represents the slant height of the cone.
no
V = (1/3*Pi*h) * (R12 + R22 + R1*R2) Where R1 and R2 are the radii of the bases, and h is equal to the height of the truncated cone.
m= (pieD + pied)/2 x height x thickness x density(kg/m^3)
A truncated cone is basically a cone with it's tip cut off.
sqrt( (R-r)^2 + h^2)where:R = radius of larger endr = radius of smaller endh = height of truncated cone
volume/(1/3*pi*(R1^2+R1*R2+R2^2))=height
The answer will depend on what information you have.
Volume of a cone = 1/3*base area*height
Volume of a cone = 1/3*pi*radius2*height
The volume of a cone is one third the volume of a cylinder of the same height. The volume of a cylinder is πr2h, so the volume of a cone is 1/3πr2h.