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V=1/3*pi*(R12+R1*R2+R22)*h
V = volume
pi = 3.142
R1 = Radius of the base
R2 = Radius of the top
h = height of the truncated cone
by my algebra, same as:
V=1/2*pi*(R12+R22)*h
The alternative algebra is not correct. Using the same positive values for R1 and R2 and the answers are not equivalent. The formula at the top matches Wikpedia and other sources on the web.
If d1 and d2 are the cone diameters and l is the length along the side, then the development is a sector with 2 radii; r1 and r2 over an angle that I'll call P (cos I don't see any variable letters).
The difference between r1 and r2 will be l, the length
The angle of the sector in degrees: P = 360(d2-d1)/(2l)
and r1 = (360 x d1)/(2 x P)
and r2 = r1 + l
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no
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