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How many combinations of three digits can be made using each digit only once in each combination?
You have a three digit number that can only use each digit once in combination. Therefore, a number like 456 is acceptable, but 455 or 101 or 222 is not acceptable. I think you can solve the problem in the following manner. There are 10 possible digits (0-9) that can be used in the first number. For the second number there are only 9 possible since you cannot repeat one of the first. For the third number there are only 8 possible since again you cannot repeat any of the first two. You multiply the possibilities for each digit to get our answer. 10 * 9 * 8 = 720 There are 720 possible combinations.
What else can I help you with?
How many three digit combinations can be made?
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
How many 3 digit combinations there 0-9?
The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.
How many different combinations can you get from 1855?
Twelve in all: One of 4 digits, Three of 3 digits, Four of 2 digits, Three of 1 digit, and One with no digits. In mathematical terms, the last IS a combination, but in common usage, probably not.
What are the possible combinations for a lock with 3 wheels and the digits 0 to 9?
The short answer is 1000. This is very easy to visualise: Simply consider each number in the combination to be a digit in a decimal number. We then end up with a three-digit number. Such a three-digit number ranges in value from 000 to 999, or 1000 unique combinations.
How many different three digit combinations can be made from numbers 0 1 2 3 4 5 6 7 8 9?
There are 720 combinations if you use each of the digits only once per combination.
How many 3 digit combinations 000 to 999 can be made?
There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.
What is a 3 digit code?
A three-digit code is a numerical sequence consisting of three digits, ranging from 000 to 999. It is often used for various purposes, such as security codes, combination locks, or PINs for accounts. Each digit can be any number from 0 to 9, allowing for a total of 1,000 possible combinations.
How many combination of three digits of 0-9 will add up to 10?
There are 13 combinations.
How many three digit whole numbers have the sum of their digits equal five?
To find the number of three-digit whole numbers where the sum of the digits equals five, we can represent the three-digit number as (abc), where (a), (b), and (c) are the digits and (a \neq 0) (since (a) is the hundreds place). The equation is (a + b + c = 5). The possible values for (a) (from 1 to 5) lead us to calculate combinations for each case. For each value of (a): (a = 1): (b + c = 4) → (5 combinations: (0,4), (1,3), (2,2), (3,1), (4,0)) (a = 2): (b + c = 3) → (4 combinations: (0,3), (1,2), (2,1), (3,0)) (a = 3): (b + c = 2) → (3 combinations: (0,2), (1,1), (2,0)) (a = 4): (b + c = 1) → (2 combinations: (0,1), (1,0)) (a = 5): (b + c = 0) → (1 combination: (0,0)) Adding these combinations gives a total of (5 + 4 + 3 + 2 + 1 = 15) three-digit whole numbers with the sum of their digits equal to five.
How many three digit combinations can be formed using 123456?
Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216
How many 3 digit combinations can be made from 0 to 6 digits?
I'll assume that you mean " ... from the digits 0, 1, 2, 3, 4, 5, and 6 ?" . -- If the same digit can appear more than once in the same combination, then there are (7 x 7 x 7) = 343 possibilities. -- If the three digits in one combination must all be different digits, then there are (7 x 6 x 5) = 210 possibilities. -- If the combinations are actual cou nting numbers, and so the first digit can't be 'zero', then there are (6 x 6 x 5) = 180 possibilities.
How many combination of three digits can be made from the number 0-9 that's larger than 15?
We notice that you said "combinations of three digits". You didn't say "3-digit numbers".There are (10 x 10 x 10) = 1000 combinations of three digits.The only combinations of 3 digits that form numbers less than 15 are 000, 001, 002, . . .012, 013, and 014. There are 15 of those.So the remaining (1000 - 15) = 985 are all larger than 15.
