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49 b in the n l?
49 Balls in the National Lottery
What is the value of N when 49-N equals 24?
25
What is the sum of all the odd numbers from 1 to 49?
The given series is: 1, 3, 5, 7, 9,... 49. The series is an Arithmetic Progression because the difference between any two consecutive terms is 2(a constant). In this A.P. first term(a) = 1, last term(l) = 49 and common difference(d) = 2. nth term of an A.P. is given by an = a + (n-1)d 49 = 1 + (n-1)x2 48 = (n-1)x2 n-1 = 24 n = 25 So there are 25 terms in this A.P. Sum of n terms of an AP is given by: Sn = n/2 x (a + l) S25 = 25/2 x (1 + 49) S25 = 25/2 x 50 S25 = 25 x 25 S25 = 625. So sum of odd numbers from 1 to 49 is 625.
What is 49 B in the L?
49 Balls in the (British) Lottery
What is 49 over 3 as a percent?
49/3 = n/100 n = 4900/3 = 1633.33 %
How many 8 numbers combinations can you make from the numbers 1 to 49?
nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.
Is 49 a triangular number?
No. ---- The nth triangular number (n must be a whole number > 0) is given by: tn = 1/2 n(n+1) Testing for 49: 1/2 n(n+1) = 49 → n2 + n - 98 = 0 → n = (-1 ± √393)/2 but 393 is not a square number, so n cannot be a whole number which it must be for a triangular number; thus 49 is not a triangular number.
What does this ditloid mean 49 b in the l?
49 Balls in the Lottery (UK)
What is the simplest form of n7 over 49?
n7/49 = n/7
Why is it said that poisson distribution is a limiting case of binomial distribution?
This browser is totally bloody useless for mathematical display but...The probability function of the binomial distribution is P(X = r) = (nCr)*p^r*(1-p)^(n-r) where nCr =n!/[r!(n-r)!]Let n -> infinity while np = L, a constant, so that p = L/nthenP(X = r) = lim as n -> infinity of n*(n-1)*...*(n-k+1)/r! * (L/n)^r * (1 - L/n)^(n-r)= lim as n -> infinity of {n^r - O[(n)^(k-1)]}/r! * (L^r/n^r) * (1 - L/n)^(n-r)= lim as n -> infinity of 1/r! * (L^r) * (1 - L/n)^(n-r) (cancelling out n^r and removing O(n)^(r-1) as being insignificantly smaller than the denominator, n^r)= lim as n -> infinity of (L^r) / r! * (1 - L/n)^(n-r)Now lim n -> infinity of (1 - L/n)^n = e^(-L)and lim n -> infinity of (1 - L/n)^r = lim (1 - 0)^r = 1lim as n -> infinity of (1 - L/n)^(n-r) = e^(-L)So P(X = r) = L^r * e^(-L)/r! which is the probability function of the Poisson distribution with parameter L.
When the smaller of two consecutive integers is added to four times the larger the result is 49?
Let the smaller integer be ( n ) and the larger integer be ( n + 1 ). The equation based on the problem statement is ( n + 4(n + 1) = 49 ). Simplifying this gives ( n + 4n + 4 = 49 ), or ( 5n + 4 = 49 ). Solving for ( n ) gives ( 5n = 45 ), so ( n = 9 ). Thus, the two consecutive integers are 9 and 10.
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