26 46
.
alternating numbers, difference halved each time
88 - 64 = 24
44 - 32 = 12 = 64 - 52
12/2 = 6 = 32 - 26 = 52 - 46
last is 6/2 = 3 (nothing after that as 3/2 is not a whole number)
26 - 23 = 3 = 46 - 43
.
88 44 64 32 52 26 46 23 43
78 100
12 12
24, 65.
The next two numbers in the sequence are... 45 & 54.
The next three numbers are: 87, 141, 228. Each number in the sequence after the first two is the sum of the previous two numbers. This is a variation of the Fibonacci sequence which starts with 1, 1, ... (and then continues ..., 2, 3, 5, 8, 13, ...).
114
3 1.5
12 - 5(n-1)
392
11, -10, 9
Since each term appears to be half of the previous term, the next two in this sequence would appear to be: 6, 3.
17?
The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2