26 46
.
alternating numbers, difference halved each time
88 - 64 = 24
44 - 32 = 12 = 64 - 52
12/2 = 6 = 32 - 26 = 52 - 46
last is 6/2 = 3 (nothing after that as 3/2 is not a whole number)
26 - 23 = 3 = 46 - 43
.
88 44 64 32 52 26 46 23 43
12 12
24, 65.
The next two numbers in the sequence are... 45 & 54.
The next three numbers are: 87, 141, 228. Each number in the sequence after the first two is the sum of the previous two numbers. This is a variation of the Fibonacci sequence which starts with 1, 1, ... (and then continues ..., 2, 3, 5, 8, 13, ...).
114
3 1.5
12 - 5(n-1)
11, -10, 9
392
The pattern in the given sequence is multiplying each number by 10. So, the next numbers in the sequence would be obtained by multiplying 120 by 10, resulting in 1200, and then multiplying 1200 by 10, yielding 12000. Therefore, the next numbers in the sequence would be 1200 and 12000.
Since each term appears to be half of the previous term, the next two in this sequence would appear to be: 6, 3.
17?