If you're referring to an English Billiards table (ie the table they also play snooker on), then the Rules define the measurements thus:
Dimensions
(a) The playing area within the cushion faces shall measure 11 ft 8½in x 5ft 10in (3569mm x 1778mm) with a tolerance on both dimensions of +/_ ½ in (+/_ 13mm).
Generally referred to as 12' x 6'
It is 2*(Length + Width).
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
It is 2*(Length + Width).
Conventionally length is the longer dimension.
Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.
77 in
Width: 7 m Length: 13 m Check: 7*13 = 91 m2
With measuring tape.
The length is 44 1/2 feet, and the width is 39 1/2 feet
yo brotha!
8m Let the width of the table be w; then its length is w + 2. Area = length x width 80 = (w + 2)w w2 + 2w - 80 = 0 (w + 10)(w - 8) = 0 w = -10 or 8 As the width must be positive, it is 8m.
Is the 60 inches measured diagonally from corner to corner (as is a TV screen)? If the 60 inches is the length, then what is the width? Length times by the width will give you the square measurement of the table.