The diagonal length is about 18.44 inches.
3.606 inches (rounded)
13 57/64 "
To find the length of the diagonal of the pool table, you can use the Pythagorean theorem. The formula is ( d = \sqrt{l^2 + w^2} ), where ( l ) is the length and ( w ) is the width. Plugging in the values, ( d = \sqrt{95^2 + 51^2} ), which equals ( d = \sqrt{9025 + 2601} = \sqrt{11626} ). Therefore, the diagonal is approximately 107.84 inches.
length of diagonal of 20 of a 20 feet and 15 width.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal length is about 18.44 inches.
3.606 inches (rounded)
28 in
Using Pythagoras' theorem the diagonal works out as 51 inches
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
13 57/64 "
To find the length of the diagonal of the pool table, you can use the Pythagorean theorem. The formula is ( d = \sqrt{l^2 + w^2} ), where ( l ) is the length and ( w ) is the width. Plugging in the values, ( d = \sqrt{95^2 + 51^2} ), which equals ( d = \sqrt{9025 + 2601} = \sqrt{11626} ). Therefore, the diagonal is approximately 107.84 inches.
7 inches diagonal top to bottom
Using Pythagoras' theorem it is about 10.81665383 inches.
Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.
length of diagonal of 20 of a 20 feet and 15 width.