The diagonal length is about 18.44 inches.
3.606 inches (rounded)
13 57/64 "
length of diagonal of 20 of a 20 feet and 15 width.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal length is about 18.44 inches.
3.606 inches (rounded)
28 in
Using Pythagoras' theorem the diagonal works out as 51 inches
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
13 57/64 "
7 inches diagonal top to bottom
Using Pythagoras' theorem it is about 10.81665383 inches.
length of diagonal of 20 of a 20 feet and 15 width.
Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764