55 is.
The nth term of the sequence 2n + 1 is calculated by substituting n with the term number. So, the tenth term would be 2(10) + 1 = 20 + 1 = 21. Therefore, the tenth term of the sequence 2n + 1 is 21.
2 and one tenth = 13/10 in improper fraction2 1/10:= [(10 * 2)+1]/10= [12+1]/10= 13/10 in improper fraction
recursive rule: term(n+1) = term(n) + (n) also, n starts at 0 and term(1)=3 term(1) = 3 ; (n=0) term(2) = term(1) + (1) = 4 term(3) = term(2) + (2) = 6 term(4) = term(3) + (3) = 9 term(5) = term(4) + (4) = 13 . . .
1/2
3/4 - 1/10 = 15/20 - 2/20 = 13/20
As an improper fraction it is 13/2, as a mixed number it is 6 1/2
1/5 one tenth of 2:= 1/10 of 2= 1/10 * 2= 1/10 * 2/1= 2/10 or 1/5
-8
3n-2
2
It is: 1 1 2 3 5 8 13 and 21 which is the 8th term
20