2 and one tenth = 13/10 in improper fraction2 1/10:= [(10 * 2)+1]/10= [12+1]/10= 13/10 in improper fraction
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
recursive rule: term(n+1) = term(n) + (n) also, n starts at 0 and term(1)=3 term(1) = 3 ; (n=0) term(2) = term(1) + (1) = 4 term(3) = term(2) + (2) = 6 term(4) = term(3) + (3) = 9 term(5) = term(4) + (4) = 13 . . .
1/2
As an improper fraction it is 13/2, as a mixed number it is 6 1/2
3/4 - 1/10 = 15/20 - 2/20 = 13/20
1/5 one tenth of 2:= 1/10 of 2= 1/10 * 2= 1/10 * 2/1= 2/10 or 1/5
-8
3n-2
It is: 1 1 2 3 5 8 13 and 21 which is the 8th term
2
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term