-8
It is a + 8d where a is the first term and d is the common difference.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
From any term after the first, subtract the preceding term.
14112027
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
It is a + 8d where a is the first term and d is the common difference.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
100 - 13(4) = 48 or 100 + 13(4) = 152. (It was not stated whether the difference given is [term - preceding term] or [term - succeeding term]. * * * * * The common difference is defined as [term - preceding term] so the first answer is the correct one: 100 - 13*4 = 48
From any term after the first, subtract the preceding term.
14112027
If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
6
10n + 1
100 + 13(-4) = 100 - 56 = 48