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What is the nth term in the arithmetic sequence?

It is a + 8d where a is the first term and d is the common difference.


What is the 14th term in an arithmetic sequence in which the first term is 100 and the common difference is -4?

What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48


How do you find the 100th term of the sequence?

a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.


If the common difference in the arithmetic sequences for and the 20th term is 36 what is the first term?

In an arithmetic sequence, the nth term can be expressed as ( a_n = a + (n-1)d ), where ( a ) is the first term and ( d ) is the common difference. Given that the common difference ( d ) is 36 and the 20th term ( a_{20} = a + 19d ), we can set up the equation ( a + 19(36) = a + 684 ). To find the first term, we need additional information about the value of the 20th term; without that, we cannot determine the exact value of the first term ( a ).


What is the 14 term in arithmetic sequence in which the first term is 100 and the common difference is -4?

100 - 13(4) = 48 or 100 + 13(4) = 152. (It was not stated whether the difference given is [term - preceding term] or [term - succeeding term]. * * * * * The common difference is defined as [term - preceding term] so the first answer is the correct one: 100 - 13*4 = 48


Explain how to find the common difference of an arithmetic sequence?

From any term after the first, subtract the preceding term.


What is the first term 2 common difference of 3?

In an arithmetic sequence, the first term is the starting value, and the common difference is the amount added to each subsequent term. If the first term is 2 and the common difference is 3, the sequence begins with 2 and each following term is obtained by adding 3. Thus, the sequence would be 2, 5, 8, 11, and so on. The nth term can be calculated using the formula: ( a_n = 2 + (n-1) \times 3 ).


WHAT ARE THE FIRST THREE OF AN ARITHMETIC SEQUENCE WHOSE LAST TERM IS IF THE COMMON DIFFERENCE IS -5?

To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).


The nth term -4,-1,4,11,20,31?

14112027


What is the common difference when the first term of a sequence is 12 and the seventh term is 36 and the last term is 144?

If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.


How do you find the nth term of an arethmetic sequence?

The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.


What is the formula for the nth term of this sequence 14 22 30 38 46?

Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.