Yes, there is a divisibility test known as casting out 7s. It is based on congruences which forms part of Mathematical Number Theory. The process is complicated and is of limited practical use.
When you divide 10 by 7 there is a remainder of 3, when 100 is divided by 7 the remainder is 2.
This is written 10 Ξ 3, 10² Ξ 2, 10³ Ξ -1, 10⁴Ξ -3, 10⁵ Ξ -2, 10⁶ Ξ 1 (mod 7)
Consequently, N Ξ a₀ + 3a₁+ 2a₂-a₃-3a₄-2a₅ + a₆ .....(mod 7)
The process is best illustrated with an example : To check if 141589 is divisible by 7 then:-
N Ξ 141589 Ξ 9 + 3x8 +2x5 -1 -3x4 -2x1 = 9 + 24 + 10 - 1 - 12 - 2 = 28 Ξ 0 (mod 7)
The final part of the statement 28 Ξ 0 (mod 7) simply tell you that 28 is wholly divisible by 7 and there is no remainder. Consequently 141589 is divisible by 7.
4 times table 4,8,12,16,20,24,28,32,36,40,44,48 5 times table 5,10,15,20,25,30,35,40,45,50,55,60 6 times table 6,12,18,24,30,36,42,48,54,60,66,74 7 times table 7,14,21,28,35,42,49,56,63,70,77,84 8 times table 8,16,24,32,40,48,56,64,72,80,88,96 9 times table 9,18,27,36,45,54,63,72,81,90,99,108 4 times table 4,8,12,16,20,24,28,32,36,40,44,48 5 times table 5,10,15,20,25,30,35,40,45,50,55,60 6 times table 6,12,18,24,30,36,42,48,54,60,66,74 7 times table 7,14,21,28,35,42,49,56,63,70,77,84 8 times table 8,16,24,32,40,48,56,64,72,80,88,96 9 times table 9,18,27,36,45,54,63,72,81,90,99,108
No, 124 is not a multiple of 7 so does not appear in the 7 times table.
The number must be divisible by 9, 23 and 41, so all three of the following conditions must be met.Divisibility by 9 requires you to check the sum of the digits is divisible by 9.Divisibility by 23 requires you to add 7 times the last digit to the rest. The answer must be divisible by 23 directly.For divisibility by 41, subtract 4 times the last digit from the rest. The answer must be divisible by 23 directly.In each case, the additions or subtractions can be repeated so as to make the answer easier to test for divisibility.
you have to separate them and if both of them are in the 7 times table it is. eg.3521 is it divisible by 7 35 + 21 the 35 is in the 7 timetable and so is the 21 so there both divisible by 7. another eg.1442 14 + 21 14 is divisible by 7 and so is 21 yes it is . thank u
63.
The 7 times table are multiples of 7
No
The special divisibility rule of 17 is "Take the difference of the rest of the digits and the last digit times 5." For instance: 17 1 - 7 * 5 = 1 - 35 = -34 which is divisible by 17.
7
28 7
No.
Yes.