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Fritz trip takes 36 minutes but the train takes 20 minutes find the distance fritz travels to work if the train travels an average of 48 miles per hour faster than his driving?
Wiki User
∙ 10y ago
Suppose the distance is D.
Then, Fritz takes 36 minutes = 36/60 hours so Fritz travels at D*60/36 = 5D/3 mph.
Then the train travels at 5D/3 + 48 mph
So the train takes D/(5D/3 + 48) hours = 20 minutes
Therefore
D/(5D/3 + 48) = 1/3
D = 1/3*(5D/3 + 48)
3D = (5D/3 + 48)
9D = 5D + 144
4D = 144
So D = 36 miles
Wiki User
∙ 10y ago
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