To draw a perfect circle you will need a drawing compass. To draw a circle you will need a pencil and paper. Starting at the top centre of the paper, place the point of the pencil. Curving around to either the right or the left which ever preferred Guide the pencil all the way around to the starting position making sure that it is symmetrical all the way round. There you have your circle. You may want to use a drawing compass to assist you in drawing a perfect circle. If you do not have a drawing compass you can improvise with a thumb tack and some string. Tie one end of the string to the tack and pin it where you want the centre of your circle to be. Tie the other end to your pencil. Keep the string stretched and move the pencil around the pin to draw a circle. You can change the size of the circle by changing the length of the string.
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In a circle that has a radius of one you use Pythagorean theorem to derive the sine, cosine and tangent formulas. Draw a circle around the origin on graph paper. The sine is the line segment from the point where the side of the angle intersects down to the x-axis. etc.
Yes. Angles are used to draw pie charts so that each portion has an equal amount of the circle by the total.
That is the definition. If you take your unit circle (a circle with radius 1 centered at the origin (0,0). you start at (1,0) and go counterclockwise around the circle 90° you end up at (0,1) that 0 is the cosine of the angle 90° In fact, you don't even need the unit circle. Take a circle of any radius r, and draw a ray at 90 degrees. This will intersect the y-axis. So as above, the coordinates are (0,r) (instead of (0,1)) so cos(90 degrees)=x/r=0/r=0
To find the sin/cos at a given point on the unit circle, draw a radius to that point. Then break the radius into components - one completely horizontal and one completely vertical. The sine is the vertical component, the cosine is the horizontal component.
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.