Suppose the sides are a, b and c with c being the hypotenuse.
Then 1/2*a*b is the area which is known. Therefore b = 2*area/a
Also, by Pythagoras, c = sqrt(a2 + b2) so that, using the previous result, c can be expressed in terms of a.
So, you now have a + b + c = perimeter where both b and c can be expressed in terms of a.
This gives a quadratic equation that can be solved for a. The two solutions are a and b, since flipping the triangle will swap the base and height.
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area=(1/2)*base*height
You cannot find the area of a 'right angle' . A 'right angle' is a measure of 'spread' between two intersecting lines. However, if you mean 'the area of a right-angled triangle?' Then for ALL triangles it is A = 0.5 X base length X perpendicular height length. For a right-angled triangle , the two lines that form the right angle are the base length and the perpendicular height length. NB 'Perpendicular' means two lines intersecting at right angles (90 degrees).
an angle that forms a linear pair with one of the interior angles of the triangle.
When placed next to any angle on a triangle, the theta symbol (θ) represents that missing angle.
It means the ratio of the opposite angle to the hypotenuse of a triangle for angle "x". This is for a right triangle.