-16t2 + 64t + 1224 = 0
Multiply both sides by -1
16t2 - 64t - 1224 = 0
Divide both side by 8
2t2 - 8t - 153 = 0
Cannot be factored so use the formula (-b (+ or -)(root of b2 - 4ac)) / 2a
16t2 + vt - S = 0 This is in the general form of the quadratic equation, and the general quadratic solution can be applied directly. t = [ (-v) plus or minus the square root of (v2 + 64S) ] all divided by 32.
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
100t -16t2 = 0 t4(25-4t) = 0 t = 0 or t = 25/4
F(t) = h - 16t2
16t2 - 37t + 20 = 0 Using the quadratic formula, t = [37 +/- sqrt(372 - 4*16*20)]/(2*16) = [37 +/- sqrt(89)] / 32 ie t = 0.861438 or t = 1.451062
There are no integer roots of this equation. Using the quadratic formula gives roots of 1.34 and 3.04 plus or minus loose change in each case.
Do you mean f(t) = -16t^2 - 48t + 160? This is a function, which can't be "solved" as it is. - you could factor it: -16(t + 5)(t - 2) - you solve for f(t) = 0: t = 2, -5
69(2)-16(2)2 plug in 2 69(2)-16(4) order of operations 138-64 74
A pebble is dropped from the top of a 144-foot building. The height of the pebble h after t seconds is given by the equation h=−16t2+144 . How long after the pebble is dropped will it hit the ground?Interpretationa) Which variable represents the height of the pebble, and in what units?b) Which variable represents the time in the air, and in what units?c) What equation relates the height of the object to its time in the air?d) What type of equation is this?e) What are you asked to determine?
0,16 1,49
The question got cut off. You simply work with the quadratic equation. For example, if you want to know when it gets to the ground, you set the position, which is s(t), equal to -288, and solve the resulting equation for "t". You can use the quadratic formula to do that.
Substitute the 2 in for t.38(2)-16(2)^276-64=12