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How do you solve this logarithmic equation -3 plus ln x equals 5?
-3 + ln(x) = 5 ln(x) = 8 eln(x) = e8 x = e8 x =~ 2981
How do you find the inverse log of a number?
AnswerLet x and y be any real numbers:log x = yx = log inv (y) = 10^yExample:pH =13.22 = -log [H+]log [H+] = -13.22[H+] = inv log (-13.22) = 10^(-13.22)[H+] = 6.0 x 10-14 MFINDING ANTILOGARITHMS using a calculator (also called Inverse Logarithm)Sometimes we know the logarithm (or ln) of a number and must work backwards to find the number itself. This is called finding the antilogarithm or inverse logarithm of the number. To do this using most simple scientific calculators,enter the number,press the inverse (inv) or shift button, thenpress the log (or ln) button. It might also be labeled the 10x (or ex) button.Example 5: log x = 4.203; so, x = inverse log of 4.203 = 15958.79147..... (too many significant figures)There are three significant figures in the mantissa of the log, so the number has 3 significant figures. The answer to the correct number of significant figures is 1.60 x 104.Example 6: log x = -15.3;so, x = inv log (-15.3) = 5.011872336... x 10-16 = 5 x 10-16 (1 significant figure)Natural logarithms work in the same way:Example 7: ln x = 2.56; so, x = inv ln (2.56) = 12.93581732... = 13 (2 sig. fig.)Application to pH problems:pH = -log (hydrogen ion concentration) = -log [H+] Example 8: What is the concentration of the hydrogen ion concentration in an aqueous solution with pH = 13.22? pH = -log [H+] = 13.22log [H+] = -13.22[H+] = inv log (-13.22)[H+] = 6.0 x 10-14 M (2 sig. fig.)
How do you solve this logarithmic equation -3 plus ln x equals 5?
-3 + ln(x) = 5 ln(x) = 8 eln(x) = e8 x = e8 x =~ 2981
What exponential equation is equivalent to the logarithmic equation e exponent a equals 47.38?
The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)
How do you solve this logarithmic equation 3x plus 7 equals 20?
To be logarithmic the equation would be, ( otherwise just linear ) 3x + 7 = 20 subtract 7 from each side 3x = 13 now, you know the answer is between x = 2 and x = 3, so I use natural logs both sides ln(3x) = ln(13) as this is a logarithmic operation you can bring down the x in front of the ln sign on the left x ln(3) = ln(13) divideboth sides by ln(3) x = ln(13)/ln(3) ( not ln(13/3)!!!!! ) x = 2.334717519 -------------------------check in original equation 3(2.334717519) + 7 = 20 13 + 7 = 20 20 = 20 --------------checks
Which logarithmic equation is equivalent to the exponential equation below ea 60?
ln 60 = a
What is the logarithmic equation of finding the relationship between two variables?
A basic logarithmic equation would be of the form y = a + b*ln(x)
What is the given logarithmic equation for lnx2.35?
If the equation was ln(x) = 2.35 then x = 10.4856, approx.
What logarithmic equation is equivalent to ea equals 35?
hanks to the limitations of the browser through which questions are posted, it is not clear what the question is but, here goes: If the question was ea = 35, then the answer is a = ln(35) where ln are the natural logarithms.
How do you solve ln 5 plus ln x equals 1?
5 + (-4) = 1 x = -4
How can you use logarithmic and exponential equations and properties to solve half-life and logistic growth scenarios?
For an exponential function: General equation of exponential decay is A(t)=A0e^-at The definition of a half-life is A(t)/A0=0.5, therefore: 0.5 = e^-at ln(0.5)=-at t= -ln(0.5)/a For exponential growth: A(t)=A0e^at Find out an expression to relate A(t) and A0 and you solve as above
How do you rewrite equation T equals 101.3e to the H over 26200 power so that you solve for H?
T = 101.3 eH/26,200eH/26,200 = T / 101.3H/26,200 = ln(T/101.3)H = 26,200 ln(T/101.3)
Are there equations that are neither linear nor quadratic?
There are many equations that are neither linear nor quadratic. A simple example is a cubic equation, such as y = x3, or a logarithmic equation, such as y = ln(x).
How do you solve for x 3 ln x - ln 3x equals 0?
3 ln(x) = ln(3x)ln(x3) = ln(3x)x3 = 3xx2 = 3x = sqrt(3)x = 1.732 (rounded)
