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In the equation ln(x) = 5, the solution is x = (about) 148.4. To solve, simply raise e to the power of both sides and reduce...

ln(x) = 5

eln(x) = e5

x = 148.4

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Q: How do you solve this logarithmic equation ln x equals 5?
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How do you solve this logarithmic equation -3 plus ln x equals 5?

-3 + ln x = 5 Add '3' to boths sides Hence ln x = 8 'ln' is logarithms to the natural base , which is 2.718281.... = 'e' Hence log(e) x = 8 x = e^(8) x = 2.71828...^8) = 2980.95798... NB One the calculator you will find two buttons, viz. 'log' & 'ln'. Log is logarithsm to base '10' Ln is logarithms to base 'e' = 2.71828.... ( The exponential .


How do you find the inverse log of a number?

AnswerLet x and y be any real numbers:log x = yx = log inv (y) = 10^yExample:pH =13.22 = -log [H+]log [H+] = -13.22[H+] = inv log (-13.22) = 10^(-13.22)[H+] = 6.0 x 10-14 MFINDING ANTILOGARITHMS using a calculator (also called Inverse Logarithm)Sometimes we know the logarithm (or ln) of a number and must work backwards to find the number itself. This is called finding the antilogarithm or inverse logarithm of the number. To do this using most simple scientific calculators,enter the number,press the inverse (inv) or shift button, thenpress the log (or ln) button. It might also be labeled the 10x (or ex) button.Example 5: log x = 4.203; so, x = inverse log of 4.203 = 15958.79147..... (too many significant figures)There are three significant figures in the mantissa of the log, so the number has 3 significant figures. The answer to the correct number of significant figures is 1.60 x 104.Example 6: log x = -15.3;so, x = inv log (-15.3) = 5.011872336... x 10-16 = 5 x 10-16 (1 significant figure)Natural logarithms work in the same way:Example 7: ln x = 2.56; so, x = inv ln (2.56) = 12.93581732... = 13 (2 sig. fig.)Application to pH problems:pH = -log (hydrogen ion concentration) = -log [H+] Example 8: What is the concentration of the hydrogen ion concentration in an aqueous solution with pH = 13.22? pH = -log [H+] = 13.22log [H+] = -13.22[H+] = inv log (-13.22)[H+] = 6.0 x 10-14 M (2 sig. fig.)