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Q: How do you solve for x 3 ln x - ln 3x equals 0?

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Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.

6x2 = -7x -2 6x2 + 7x + 2 = 0 6x2 + 3x + 4x + 2 = 0 3x(2x + 1) + 2(2x + 1) = 0 (2x + 1)(3x + 2) = 0 2x + 1 = 0 or 3x + 2 = 0 So, x = -1/2 or -2/3

If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2

so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1

3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.

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3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3

5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3

(3x+4)(3x-4)=0 x=±4/3

x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.

2x(3x+6) = 0 x = 0 or x = -2

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-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3

2x+3x-2=0=5x=0+2=5x=2=5x_5=2_5=x=0.4

3x2 + x - 2 = 0(3x - 2) (x + 1) = 0x = + 2/3x = -1

x = 25 / 3squared + 5

If 3X-27= 0 then X=9

5 y = 15 y = 3 3x - y = 3x-3=0 3x -3 = 0 3x = 3 x = 1

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