If the angle is x radians, then tan(x) = 1/20 = 0.05
So x = tan-1(0.05) = 0.04996 radians = 2.86 degrees (approx)
It is a trigonometric function which converts the angle into a ratio.If the angle A is measured in radians, thencos(A) = 1 - A^2/2! + A^4/4! - a^6/6! + ...
It is a fraction between 1/4 and 1/2.
Cotangent is ' 1/tangent' or ' Cosine / Sine'.
Here is an 'aide memoire'. SOH, CAH, TOA. Expanding this aide. SOH ; is Sine , Oppositre, and Hypotenuse. CAH ; is Cosibe, Adjacent and Hypotenuse. TOA ; is Tangent, Opposite and Adjacent. To put these in algenraic format . Sine(angle) = opposite / hypotenuse Cosine(angle) = adjcent / hypotenuse Tangent(angle) = opposite/ adjacent. And in algenraic short-hand format. Sin(angle) = O/H Cos(angle) = A/H Tan(angle) = O/A For any given Right-angled triangle, the Hypotenuse is always the side opposite to the right angle. Taking one of the other anglers. Then the Opposite is the side length oppisite to the given angle. Then the Adjacent is the side length to the given angle. NB Taking the third angle, then the opposite(O) and the adjacent(A) ' swop places. The above three equations can all be algebraically rearranged. 'Sine' is shown, bit the other two can also be rearranged. Sin(angle) = O/H H X Sin(angle) = O [Sin(angle)] / O = H Angle = Sin(-1) [O/H] or ArcSin [O/H]. An example A right angled triangle of hypotenuse '2'. and an angle of 30 degrees. Then Sin(30) = O/2 On your calculator ; Sin(30) = 1/2 or 0.5 Substituting. 1/2 = O / 2 Algebraically rearrange O = 2 X 1/2 = 2/2 = 1/1 = 1 So the opposite side is equal to '1'. Correspondingly Sin(angle) = O/H = 1/2 Then Angle = Sin^(-1)[1/2] On your calculator, using the 'inverse/arcsin' button of Sin Then angle = 30 degrees. These work for any Trig. Functions. However, for any given value of an angle, you will have some 'horrible' decimal number. Sin(79) = 0.98167183.... usuallu shortened to 4 d.p. at 0.9817. or 6 d.p. 0.981672 Hope that helps!!!!!
First, if the angle is 360° or more, find the remainder of the angle divided by 360 - this is as 360° represents a full turn. If you have a 360° protractor just measure off the angle. If you only have a 180° protractor, then there are two ways it can be done as the protractor is marked so that 0° - 180° can be measured from either end of the base line: Method 1: excess over 180° 1) Subtract 180° from the angle to get the excess over 180°. 2) Place the protractor on the line, centred on the vertex of the angle on the left of the line, with the top 0°/180° mark on the line. 3) Measure the excess over 180° calculated in step 1 from the bottom 0° mark of the protractor. 4) Draw in the second angle arm - the reflex angle (measured clockwise) is as required. Method 2: acute/obtuse angle of the reflex angle to complete a full turn 1) Subtract the angle from 360° to get the angle which completes the full turn 2)Place the protractor on the line, centred on the angle vertex on the left of the line, with the top 0°/180° mark on the line. 3) Measure the angle to complete the full turn calculated in step 1 from the top 0° mark of the protractor (on the line). 4) Draw in the second angle arm - the reflex angle (measured clockwise) is as required. The above assume a clockwise angle is being drawn from a vertical line with the angle vertex at the bottom. For anticlockwise angles, place the protractor on the right of the line. For a non-vertical line [mentally] rotate the paper so that the first arm of the angle is vertical with the angle vertex at the bottom.
No. A percentage gradient tells you how many you go up or down for every 100 along, for example a gradient of 5% means for every 100m along you go, you will go up or down 5m. Given a percentage gradient, converting it to a decimal (by dividing by 100) will give the TAN of the angle of the slope, for example a gradient of 5% means the angle = arctan(5/100) = arctan(0.05) ~= 2.9o. The 1 in x gradient that tells you for every 1 up or down you go you go x along, for example 1 in 20 means you will go up or down 1 yd for every 20 yds along.
The angle is the arc-tan of the gradient of the line. That is to say, the tangent of that angle is the gradient of the line or the angle between the straight line and the positive x-axis. Arc tan may also be written as tan-1 but that is frequently confused with 1/tan or the cotangent function.
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If you know the gradient for a line (the m in y = mx + c) then tan-1 (m) will give you the angle between the line and the x axis. So do tan-1 for both gradients and subtract to find angle between the lines.
Remember the sum of the 3 angles of a triangle = 180degrees Let angle 1 = x angle 2 = 2x angle 3 = x-20 Sum = x + 2x + x - 20 =180o 4x - 20 = 180o 4x = 200o x = 50o 2x = 100 o x - 20 = 30o angle 1 = 50o angle 2 = 100 o angle 3 = 30o
To find the gradient of the equation 2y = 4x + 1, we first need to rewrite it in slope-intercept form, y = mx + b, where m is the gradient. Dividing by 2 on both sides gives y = 2x + 0.5. Therefore, the gradient is 2.
if it is an aluminum block stage 1 20 Nm then stage 2 angle tighten a further 240 degrees if it is a cast iron engine block stage 1 20 Nm stage 2 angle tighten a further 120 degrees then stage 2 angle tighten another 120 degrees these settings are for a petrol engine
If you mean: y = 2x+1 then the gradient is 2 and the y intercept is 1
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x+y=2 the gradient is -1
sin-1(1/20) = 3 degrees.
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