x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
(x-2)^2+y^2=64
X = y2 =====
y2=-x2-8x+6
change in Y divided by change in X. X is your field value(kilometers, miles, feet, etc) and Y is the units of your isolines(degrees, feet, meters, etc) Y2-Y1 / X2-X1 = Y2-Y1 DIVIDED BY X2-X1
Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
Select two points on the graph and suppose their coordinates are (x1, y1) and (x2, y2) then the gradient = (y1 - y2) / (x1 - x2) provided that x1 and x2 are different. If not, the gradient is not defined.
0
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
y2 - y1-------- = Gradient
Slope or gradient = (y2-y1)/(x2-x1)
to calculate the area of any straight line graph or part of a graph, you need to select two points. for example (x1,y1) and (x2,y2). once you have selected the points you put then into the equation m=delta y/delta x (change in y divided by the change in x) which is easier as m=(y2-y1)/(x2-x1) and m = the gradient
Yes, as x-y2=0
Yes beccause: (y1-y2)/(x1-x2) = gradient
X2+y2=25 (x-8)2+y2 =41