B: -tan(25)
Tan 42 degrees = 0.9004
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
tan(11o) = 0.19438 =======
tan(22.5)=0.414213562
tan 45° = 1
They are both trig values, but not equal. Tan 45 is 1 and sin 45 is 0.7071
45 degrees?
oh, yes people can get sunburnt or tan during weather near 45 degrees!
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
tan(1) = 1.5574 where the angle is measured in radians.
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
Let m be the slope in percent and theta be the angle in question. tan (theta) = m/100 theta = arctan (m/100) To verify the result, we know the following: tan 0 = 0 tan (45 degrees) = 1 = 100% tan (90 degrees) = infinity For example, if 0 < m < 100%, then 0 < theta < 45 degrees.
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
45 degrees (+/- 180k degrees for any integer k) or pi/4 radians (+/- pi*k radians for any integer k).
Yes. The tan of 45 degrees is 1.
Let's look at an right isosceles triangle (where the base angles measure 45 degrees, and legs are congruent). So that, tan 45 degrees = leg/leg = 1