45 degrees (+/- 180k degrees for any integer k)
or pi/4 radians (+/- pi*k radians for any integer k).
tan(3x)=1 3x= PI/4 x=PI/12 is the smallest positive number
First: note 3 things about cot and tan, and note the given statement:cot = 1/tantan is cyclic with a period of π, that is tan(nπ + x) = tan(x)tan is an odd function, that is tan(-x) = -tan(x)tan(π/4) = 1Now apply them to the problem:cot(π - π/4) = 1/tan(π - π/4)= 1/tan(-π/4)= 1/-tan(π/4)= 1/-1 = -1Thus:cot(π - π/4) = -1.
tan A says nothing about tan B without further information.
If sin θ = tan θ, that means cos θ is 1 (since tan θ = (sin θ)/(cos θ)) (Usually in and equation a/b=a, b doesn't have to be 1 when a is 0, but cos θ = 1 if and only if sin θ = 0) The angles that satisfy cos θ = 1 is 2n(pi) (or 360n in degrees) When n is an integer. But if sin θ = tan θ = θ, the only answer is θ = 0. Because sin 0 is 0 and cos 0 is 1 and tan 0 is 0 The only answer would be when θ = 0.
Tan(90) is an infinitely large number, and unresolved.
45*
When x = 3.806663, tan(e^x) = 1.
1/ Tan = 1/ (Sin/Cos) = Cos/Sin = Cot (Cotangent)
x = tan-1(5) = 78.69 degrees
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
3cot(A) = 4 so cot(A) = 4/3 then tan(A) = 1/(4/3) = 3/4 and so 1 - tan(A) = 1-3/4 = 1/4
Tan )x degrees) = 1.66 x degrees) = Tan^(-1) 1.66 x = 58.9348.... degrees. NB Tan^(-1) on some calculators 9is shown as 'ArcTan'.
The value of tan and sin is positive so you must search quadrant that tan and sin value is positive. The only quadrant fill that qualification is Quadrant 1.
i don't know :) XD
tan(23) = 1.58815308
tan(3x)=1 3x= PI/4 x=PI/12 is the smallest positive number
Tan(0) = 0 Remember Tan(0) = Sin(0)/Cos(0) = 0/1 And Sin(0) = 0 Hence it follows that Tan(0) = 0