Yes, except at odd multiples of pi/2 radians, where the cosine is zero so that the division is not defined.
Since secant theta is the same as 1 / cosine theta, the answer is any values for which cosine theta is zero, for example, pi/2.
The sine graph and the cosine graph are identical in shape, with the cosine graph shifted to the left by pi / 2, i.e. the sine starts at (x=0,y=0) and proceeds up with an initial slope of one, and the cosine starts at (x=0,y=1), and proceeds down with an initial slope of zero.
Cosine (0) = 1 Sin(0) = 0 The sine and cosine curves are two intertwining curves, that complement each other, hence the words 'Sine (Curve) and Cosine ( COmplementary Curve).
-1<cosine<1
The cosine of 90 degrees is zero.
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
Zero
Cosine of 90 degrees is zero.
Yes, except at odd multiples of pi/2 radians, where the cosine is zero so that the division is not defined.
The secant of an angle is the reciprocal of the cosine of the angle. So the secant is not defined whenever the cosine is zero That is, whenever the angle is a multiple of 180 degrees (or pi radians).
Since secant theta is the same as 1 / cosine theta, the answer is any values for which cosine theta is zero, for example, pi/2.
It is cosine*cosine*cosine.
The sine graph and the cosine graph are identical in shape, with the cosine graph shifted to the left by pi / 2, i.e. the sine starts at (x=0,y=0) and proceeds up with an initial slope of one, and the cosine starts at (x=0,y=1), and proceeds down with an initial slope of zero.
For a general cosine graph, they would be the maximum and minimum values, and the values of the independent variable at which these are attained.Note that the graph of y = cos(x)+2 is never equal to zero, so there may not be any roots.
Zero. Tangent = sine/cosine. sin(0) = 0 and cos(0) = 1, so 0/1 = 0.
For an angle of 90 or 270 degrees. In radians, pi / 2 and 3 x pi / 2.