Cotangent is 1 / tangent. Since tangent is sine / cosine, cotangent is cosine / sine.
in trigonometry
The tangent function is equal to the sine divided by the cosine. In quadrant III, both sin and cos are negative - and a negative divided by another negative is positive. Thus it follows that the tangent is positive in QIII.
If you know the angle's sine, cosine, or tangent, enter it into the calculator and press <inverse> sine, cosine, or tangent. On MS Calc, in Scientific Mode, using Degrees, enter 0.5, then check Inv and the press sin. You should get 30 degrees. The other functions work similarly.
sine, cosine, tangent, cosecant, secant and cotangent.
No, it does not.
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
For finding the angles in a right angled triangle the ratios are: sine = opposite divided by the hypotenuse cosine = adjacent divided by the hypotenuse tangent = opposite divided by the adjacent
Trig identity... sin/cos = tangent
Sine = -0.5 Cosine = -0.866 Tangent = 0.577
Yes, sine, cosine, tangent definitions are based on right triangles
The tangent of an angle theta is defined as sine(theta) divided by cosine(theta). Since the sine and cosine are Y and X on the unit circle, then tangent(theta) is Y divided by X. The tangent of a function at a point is the line going through that point which has slope equal to the first deriviative of the function at that point.
Cotangent is 1 / tangent. Since tangent is sine / cosine, cotangent is cosine / sine.
That is the correct spelling of "tangent" (intersecting at one point, or sine divided by cosine, or opposite side over adjacent side).
No, it is not. To be correct, the expression requires parenthesis, which are missing.
It is a trigonometric function, equivalent to the sine of an angle divided by the cosine of the same angle.
Tangent (theta) is defined as sine (theta) divided by cosine (theta). In a right triangle, it is also defined as opposite (Y) divided by adjacent (X).