The exact value of 60 degrees would be 1/2. This is a math problem.
tan(-60 degrees) = - sqrt(3)
Tan(60) = Sin(60)/ Cos(60) Sin(60) = sqrt(3)/2 Cos(60) = 1/2 Hence Sin(60) / Cos(60) = [sqrt(3) / 2] / [1/2} => sqrt(3) / 2 X 2/1 sqrt(3) Hence Tan(60) = sqrt(3) = Numerically = 1.732050808....
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.
Sin(30) = 1/2 Sin(45) = root(2)/2 Sin(60) = root(3)/2 Cos(30) = root(3)/2 Cos(45) = root(2)/2 Cos(60) = 1/2 Tan(30) = root(3)/3 Tan(45) = 1 Tan(60) = root(3) Csc(30) = 2 Csc(45) = root(2) Csc(60) = 2root(3)/3 Sec(30) = 2root(3)/3 Sec(45) = root(2) Sec(60) = 2 Cot(30) = root(3) Cot(45) = 1 Cot(60) = root(3)/3
No. Cosine, along with sec, is an even function. The odd functions are sin, tan, csc, and cot. The reason for this is because is you take the opposite of the y-value for the cosine function, the overall value of the function is not affected.Take, for example, cos(60 degrees), which equals POSITIVE 1/2.If you flip it over the x-axis, making the y's negative, it becomes cos(-60 degrees), or cos(300 degrees). This equals POSITIVE 1/2.Now let's look at an odd function. For example, sin(30 degrees) equals POSITIVE 1/2. Now take the opposite of this.sin(-30 degrees), or sin(330 degrees), equals NEGATIVE 1/2. This is because it is found in the fourth quadrant, where the y's are negative. Sine of theta, by definition, is y divided by r. If y is negative, sine is negative.
tan(-60 degrees) = - sqrt(3)
1.732
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
cot 115 deg = - tan25 deg
5400
tan(pi/3) = tan (60 degrees) = 1.732 which is square root of 3
60 degrees
Tan(60) = Sin(60)/ Cos(60) Sin(60) = sqrt(3)/2 Cos(60) = 1/2 Hence Sin(60) / Cos(60) = [sqrt(3) / 2] / [1/2} => sqrt(3) / 2 X 2/1 sqrt(3) Hence Tan(60) = sqrt(3) = Numerically = 1.732050808....
The tangent of 60 degrees is equal to the square root of 3, or approximately 1.732. This value can be derived from the properties of a 30-60-90 triangle, where the ratio of the lengths of the sides opposite the angles gives the tangent. Specifically, in a 30-60-90 triangle, the side opposite the 60-degree angle is √3 times the length of the side opposite the 30-degree angle.
IT could anywhere from 60-80 degrees. There's no exact temp.
There are 60 minutes in a degree, so 18.773'/60 = .3129 degrees, and your final value is north 27.3129o.
You have a right triangle and can use trig. Degree mode. tan(theta) = adjacent/opposite( y component ) tan( 60 degrees) = (5 m/s)/(y comp.) y component = 5 m/s)/(tan 60 degrees) = 2.887 m/s ( you can call it 3 m/s ) -----------------------------------------------