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The exact value of 60 degrees would be 1/2. This is a math problem.

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A polynomial of degree zero is a constant term

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Q: What is the exact value of tan 60 degrees?
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What is the exact value of tan -60?

tan(-60 degrees) = - sqrt(3)

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What are all the exact t-values for which tan t equals -sqrt3?

sin(60) or sin(PI/3) = sqrt(3)/2 cos(60) or cos(PI/3)=1/2 tan(60) or tan(PI/3) = sin(60)/cos(60)=sqrt(3) But we want tan for -sqrt(3). Tangent is negative in quadrant II and IV. In Quadrant IV, we compute 360-60=300 or 2PI-PI/3 =5PI/3 tan(5PI/3) = -sqrt(3) Tangent is also negative in the second quadrant, so we compute PI-PI/3=2PI/3 or 120 degrees. tan(t)=-sqrt(3) t=5PI/3 or 2PI/3 The period of tan is PI The general solution is t = 5PI/3+ n PI, where n is any integer t = 2PI/3+ n PI, where n is any integer

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What is A boat moves at an angle of 60 in a horizontal line The x component of the boats velocity is 5 m s What is its y component of velocity?

You have a right triangle and can use trig. Degree mode. tan(theta) = adjacent/opposite( y component ) tan( 60 degrees) = (5 m/s)/(y comp.) y component = 5 m/s)/(tan 60 degrees) = 2.887 m/s ( you can call it 3 m/s ) -----------------------------------------------

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