tan(-60 degrees) = - sqrt(3)
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.
the tangent of 60 degrees is 1.7321
Sin(30) = 1/2 Sin(45) = root(2)/2 Sin(60) = root(3)/2 Cos(30) = root(3)/2 Cos(45) = root(2)/2 Cos(60) = 1/2 Tan(30) = root(3)/3 Tan(45) = 1 Tan(60) = root(3) Csc(30) = 2 Csc(45) = root(2) Csc(60) = 2root(3)/3 Sec(30) = 2root(3)/3 Sec(45) = root(2) Sec(60) = 2 Cot(30) = root(3) Cot(45) = 1 Cot(60) = root(3)/3
No. Cosine, along with sec, is an even function. The odd functions are sin, tan, csc, and cot. The reason for this is because is you take the opposite of the y-value for the cosine function, the overall value of the function is not affected.Take, for example, cos(60 degrees), which equals POSITIVE 1/2.If you flip it over the x-axis, making the y's negative, it becomes cos(-60 degrees), or cos(300 degrees). This equals POSITIVE 1/2.Now let's look at an odd function. For example, sin(30 degrees) equals POSITIVE 1/2. Now take the opposite of this.sin(-30 degrees), or sin(330 degrees), equals NEGATIVE 1/2. This is because it is found in the fourth quadrant, where the y's are negative. Sine of theta, by definition, is y divided by r. If y is negative, sine is negative.
tan(-60 degrees) = - sqrt(3)
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
1.732
cot 115 deg = - tan25 deg
5400
60 degrees
tan(pi/3) = tan (60 degrees) = 1.732 which is square root of 3
IT could anywhere from 60-80 degrees. There's no exact temp.
sin(60) or sin(PI/3) = sqrt(3)/2 cos(60) or cos(PI/3)=1/2 tan(60) or tan(PI/3) = sin(60)/cos(60)=sqrt(3) But we want tan for -sqrt(3). Tangent is negative in quadrant II and IV. In Quadrant IV, we compute 360-60=300 or 2PI-PI/3 =5PI/3 tan(5PI/3) = -sqrt(3) Tangent is also negative in the second quadrant, so we compute PI-PI/3=2PI/3 or 120 degrees. tan(t)=-sqrt(3) t=5PI/3 or 2PI/3 The period of tan is PI The general solution is t = 5PI/3+ n PI, where n is any integer t = 2PI/3+ n PI, where n is any integer
There are 60 minutes in a degree, so 18.773'/60 = .3129 degrees, and your final value is north 27.3129o.
The y component of velocity can be found using trigonometry. Since the angle is 60 degrees, the formula to calculate the y component of velocity is: y component = x component * tan(angle). Given the x component of velocity as 5 m/s and the angle of 60 degrees, the y component of velocity is approximately 8.66 m/s.
First, I assume the question refers to tan(90 degrees) not Ten90' because (apart from the incorrect spelling of tan) 90' represents 90 minutes or 90/60 degrees = 1.5 degrees. The tangent of an angle is defined as the ratio of sine to cosine of the angle. When that angle is 90 degrees, the cosine is zero and so calculation of tan involves division by 0. And, in mathematics division by 0 is not infinity - it is not defined. So, tan(90) is NOT infinity. It is not defined. tan90 has a positive asymptote when you approach 90 degrees from below but has a negative asymptote when you approach from above.