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If this is a homework question, please consider trying to answer it on your own first, otherwise the value of reinforcement of the lesson will be lost on you.

To determine the trigonometry function of sin, with a period of pi, and amplitude of 1, and a vertical shift of +1, start simple and expand.

The period of sin(x) is 2 pi, so to halve that period you need sin(2x).

The amplitude of sin(2x) is 2, so to halve that amplitude you need 1/2 sin(2x).

To shift any function up by 1, simply add 1 to it, so the final answer is 1/2 sin(2x) + 1.

Note: This is very simple when you take it step by step.

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14y ago
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chinthaginjala venka...

Lvl 5
1y ago

y=a sin (bx)

given amplitude a=1

period p=2pi/b then b=2

vertical shift +1

so required function y=1+sin(2x)

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Q: What is the trig function of sin with a period of pi an amplitude of 1 and a vertical shift up of 1?
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