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cos(3t) = cos(2t + t) = cos(2t)*cos(t) - sin(2t)*sin(t) = [cos2(t) - sin2(t)]*cos(t) - 2*cos(t)*sin(t)*sin(t) = [cos2(t) - sin2(t)]*cos(t) - 2*cos(t)*sin2(t) then, since sin2(t) = 1 - cos2(t) = [2*cos2(t) - 1]*cos(t) - 2*cos(t)*[1 - cos2(t)] = 2*cos3(t) - cos(t) - 2*cos(t) + 2*cos3(t) = 4*cos3(t) - 3*cos(t)
T + 5 + 3T = 1 Simplify the terms, T and 3T (think 1 apple plus 3 apples) 4T + 5 = 1 Subtract 5 from both sides. 4T = -4 then divide both sides by 4 to get T by itself. T = -4/4 T = -1 To check, substitute T = -1 wherever you see T in your original equation. T + 5 + 3T = 1 (-1) + 5 + 3(-1) = 1 4 - 3 = 1 1 = 1 (check)
T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.
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I am assuming that the equation is 3*sin(t) = 1.5 even though the equality sign is not visible - due to the browser limitations. Then sin(t) = 1.5/3 = 0.5 So t = sin-1(0.5) which gives the principal value of t = 0.5236. The next value of t, in the domain, is pi - 0.5236 = 2.618 radians. There are no further values in the specified domain.