Divide the ordinate (y-coord) of any point on the graph by its abscissa (x-coord).
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
The x and y axes
It makes a line ,it goes through the origin, it has a constant
A straight line that goes through the origin.
It may or may not exist. Whether or not the graph goes through the origin does not in any way affect whether or not it has a derivative. A function has a derivative if it has no discontinuities, cusps, sharp corners, or vertical tangents.
At the x-intercept, y=0.2x = 0x = 0The line goes through the origin, where 'x' and 'y' are both zero.
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
To find a unit rate on a graph that goes through the origin, identify the coordinates of a point on the line (other than the origin). The unit rate is determined by calculating the slope of the line, which is the change in the y-value divided by the change in the x-value (rise over run). Since the line passes through the origin, the slope directly represents the unit rate of change between the two quantities. For example, if the point is (4, 8), the unit rate would be 8/4 = 2, indicating that for every 1 unit increase in x, y increases by 2 units.
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A radius (or radial) vector is a vector which goes through the origin. That is going directly away from (or toward) the origin. A vector that is not radial is a transverse vector
It's a slanted straight line that goes through the origin of the coordinates.
You start at the origin and go down 4, forward one. Continue doing that. Then, go up 4, back 1 starting back at the origin. Continue doing that.