Any number where all the digits add up to 3, 6, or 9 is divisible by 3. Example: 12 = 1 + 2 = 3 so 12 is divisible by 3. 259 (2 + 5 + 9 = 16 = 1 + 6 = 7 so 259 is not divisible by 3). and last 267 (2 + 6 + 7 = 15 and 1 + 5 = 6 so 267 is divisible by 3).
111 is the least positive integer divisible by 111 without remainder.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
165 is wholly divisible by 3. This is because 165 can be represented in the form k*3 = l, where k is a positive integer.
The positive integer factors of 591 are:1, 3, 197, 591
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
30, which is the smallest positive integer divisible by the first three primes: 2, 3 and 5.
2520
The positive integer factors of 12897 are: 1, 3, 9, 1433, 4299, 12897
No. A positive integer cannot be divisible by a number bigger than itself!
a positive integer evenly divisible only by itself and one.
An integer exactly divisible by at least one positive integer other than itself or 1.
90