Not hurt the pool but it can inhibit chlorine from sanitizing properly in high amounts. If its to high just drain some water out and refill with fresh.
To achieve a concentration of 80 parts per million (ppm) of cyanuric acid in 25,000 gallons of water, you need to calculate the amount in pounds. First, convert gallons to pounds using the fact that 1 gallon of water weighs approximately 8.34 pounds. Therefore, 25,000 gallons weighs about 208,500 pounds. To find the amount of cyanuric acid needed, multiply 80 ppm by the total weight of the water (208,500 pounds) and divide by 1,000,000 (to convert ppm to a weight in pounds), resulting in approximately 2.5 pounds of cyanuric acid required.
GALLONS As in: 1 gallon, 2 gallons.
Two. They need a min. of 20 gallons each.
There are two half gallons in a gallon.
Fill the 5 gallon jug Pour from the 5 gallon to fill the 3 gallon jug You now have 2 gallons in the 5 gallon jug Empty the 3 gallon jug Pour the 2 gallons from the 5 gallon jug into the 3 gallon jug Fill the 5 gallon jug Pour from the 5 gallon jug to fill the three gallon jug -- this will tale 1 gallon You now have 4 gallons in the 5 gallon jug
fill the 7 gallon bucket, dump it into the 5 gallon bucket and save the remaining 2 gallons, repeat and you have 4 gallons.
Two half-gallons = 1 gallon
The conversion from UK to US gallons is: UK gallons x 1.201 = US gallons
A gallon
Multiply Imperial gallons by 1.2 to get US gallons.
Since there are 4 quarts to the gallon - The answer is 4 gallons !
This is a ratio: whatever : treat 1 gallon : 1000 gallon ? gallon : 25 gallon First find out how much treats 1 gallon (divide both sides by 1000): 1 ÷ 1000 gallon : 1000 ÷ 1000 gallon → 0.001 gallon : 1 gallon Now find out how much treats 25 gallons (multiply both sides by 25) 25 × 0.001 gallon : 25 × 1 gallon → 0.025 gallon : 25 gallon → you need 0.025 gallons.