8x + 3 = 50 8x = 47x = 47/8x= 5 and 7/8ths
5x+4y = -3 4y = -5x-3 y = -5/4 x - 3 Slope is -5/4.
8x + 6 = 3x - 4 8x = 3x - 4 - 6 8x = 3x - 10 8x - 3x = -10 5x = -10 5x/5 = -10 x = -10/5 x = -2
-8x + 5 - 3x = -6Combine the 'x' terms on the left side:-11x + 5 = -6Subtract 5 from each side:-11x = -11Divide each side by -11:x = 1
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
8x plus 4y equals 5 is 8x + 4y = 5.
8x+4y=20 4y=-8x+20 y=-2x+5 f(x)=-2x+5
The two equations represent the same straight line.
They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.
11-4y=-5 -4y=-16 y=4
(1, 1)
6.75
4y + 4 = 3y - 5 y = -9
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
5
Add the equations: 8x - y = 8 ie 8x - 8 = y so 5x - 5(8x - 8) = -30 which is 5x - 40x + 40 = -30 ie -35x = -70 making x = 2 and y = 8.
(-1, 5)