100 telegram from the queen
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
Suppose you have a variable which grows at r% per period [year] and you want to find out how many periods, t, it will take before it grows, from a starting value of P to reach the value Q.The approximate method used by younger pupils is trial and error. This is because the y do not have the necessary mathematical knowledge.After t periods, the variable in question will have increased from P to Q whereQ = P*(1+r/100)tthen Q/P = (1+r/100)ttaking logarithms, log(Q/P) = log[(1+r/100)t] = t*log(1+r/100)and so finally, t = log(Q/P) / log(1+r/100).
P Q (/P or /Q) T T F T F T F T T F F T
p > q~qTherefore, ~p| p | q | p > q | ~q | ~p || t | t | t | f | f || t | f | t | t | f || f | t | t | f | t || f | f | t | t | t |
There are 100 questions in this quiz.
P | T T F F Q | T F T F Q' | F T F T P + Q' | F T F F The layout is the best I could do with this software. Hope it is OK.
A. T. Q. Stewart was born in 1929.
A. T. Q. Stewart died in 2010.
The starting value is Q(0) = (1/3)^(0/25) = (1/3)^0 = 1 Growth rate (per period, t) = 100*{Q(1)/Q(0)-1} = 100*{(1/3)^(1/25)/1 - 1} = 100*{0.9570 - 1} = -4.30 % approx.
The duration of Q. T. Hush is -300.0 seconds.
100 zeroes in a googal... the 'q' is a typo for a 'g'
t wer ewq qet rew er t e q q / r yi uyt wt ree rt e q q / t e r w e q $ / t e r w eti (