#include <stdio.h> #include <conio.h> void main() { int a=1,b,y,m,q; while(a<=500) { b=a; y=0; while(b!=0) { m=b%10; q=b/10; y=y+(m*m*m); b=q; } if(y==a) { printf("%d\n",a); } a++; } getch(); }SOUMYA TALREJA BHOPAL
q q h q q h q q q q w b b b b b b b d g a b q q q q q q q q q q q h h c c c c c b b b b a a b a d repeat first line q q q q q q q q q q w c c c c b b b d d c a g q= quarter note h= half note w= whole note
Suppose p = a*10^x andq = b*10^y are two numbers in scientific notation.Then p*q = (a*b)*10^(x+y)where, 1
Supposep = a*10^x andq = b*10^y are two numbers in scientific notation.Then p*q = (a*b)*10^(x+y)where, 1
No. Rational numbers are defined as fractions of whole numbers. Suppose we have two rational numbers A = m/n and B = p/q. Then their quotient is defined as A/B = (m*q) / (n*p). Since m,n,p and q are whole, the products m*q and n*p are whole as well, making A/B a rational number.
The letter o, Q, Q,m, b, c, C, u,U, and there might be more.
T then V There are five letters between B and H, four between that and M, then three, then two...
B. M. Suhara was born on 1952-10-11.
#include<stdio.h> #include<conio.h> main() { int a[10][10],b[10][10],c[10][10],m,n,i,j,p,q,op; printf("enter the order of matrix a:n"); scanf("%d",&m,&n); printf("enter the %d elements of a\n",m*); for(i=0;i<m;i++) for(j=0;j<n;j++) scanf("%d",&a[i][j]); printf("enter the order of matrix b:n"); scanf("%d",&p,&q); printf("enter the %d elements of b\n",p*q); for(i=0;i<p;i++) for(j=0;j<q;j++) scanf("%d",&b[i][j]); printf("enter the option\n"); scanf("%d",&option); switch(op) { case '+' : if(m==p&&n==q) printf("the resultant matrix c is:\n"); for(i=0;i<m;i++) for(j=0;j<n;j++) c[i][j]=a[i][j]+b[i][j]; printf("%d",c[i][j]); printf("\n"); break; case '/' : if(n==p) { for(i=0;i<m;;i++); {for(j=0;j<q;j++) {printf("%d",c[i][j]); } } c[i][j]=0; for(p=0;p<n;p++) c[i][j]=c[i][j]+a[i][p]*b[p][j]: } printf("resultant matrix is:\n"); for(i=0;i<m;;i++); {for(j=0;j<q;j++) {printf("%d\t",c[i][j]); } } printf("\n"); getch(); }
If B is between P and Q, then: P<B<Q
Search gg
a/b = 1 so a = b. Then a b = q implies that a = b = q/2 So ab = (q/2)*(q/2) = q2/4