Q: 1 2 4 8 16 32 Nth term?

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The n-th term would be: 2^(6-n) So, when n=1, it is 2^(6-1) = 2^5 = 32.

The nth term is: 3n+1 and so the next number will be 16

The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.

2 raised to the power of n+1. In other words 2 multiplied by itself n+1 times.

The nth term is n2.

Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}

Clearly, if you omit the sign, the nth. term will be 4n. The alternating sign can easily be expressed as a power of (-1), so in summary, the nth. term is (-1)n4n.

5n+1

n2

2n+1

It is 5n-4 and so the next term will be 21

tn = n2

It is: 3n+1

t(3) = 10 - 32 = 1

n^2 + 2n + 1

It is: nth term = 35-9n

It is: 16/32 is equivalent to 1/2 in its lowest terms

It means to find the generic expression for any term, not just for one specific term. For example, in the sequence 1, 4, 9, 16, 25... it should be clear that these are square numbers, which you can write as 12, 22, 32, etc. The nth. term is n2, meaning that for any number "n", term number n is n2.

The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)

The Nth term for a triangle number is: 0.5n(n+1)

Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.

The nth term is: 5-2n

8 + (74 x 6) = 75th term. nth term = 8 + 6(n-1)

Tn = 1 + 3n

3n+1

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