We note the sequence goes up in steps of '8'
Hence '8n'.
Next for step #1 4#1 ; n = 1 ; 8(1) + c = 16
8 + c = 16
c = 8
Hence the nth terms is 8n + 8
Verifications
When n = 3 ; 8(3) + 8 = 24 + 8 = 32 ( which is true).
The nth term is (36 - 4n)
[object Object]
The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.
the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.
[ 6n + 8 ] is.
The nth term is (36 - 4n)
2n
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
[object Object]
The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.
the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.
The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.
If you meant: 2 12 22 32 then the nth term = 10n-8
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
37
It appears that the nth term is (8 + 2n).- For n=12, (8 + 2n) = (8 + 24) = 32 .- For n=77, (8 + 2n) = (8 + 154) = 162.
The given sequence is a geometric sequence where each term is multiplied by 2 to get the next term. The first term (a) is 4, and the common ratio (r) is 2. The nth term of a geometric sequence can be found using the formula ( a_n = a \cdot r^{(n-1)} ). Therefore, the nth term of this sequence is ( 4 \cdot 2^{(n-1)} ).