answersLogoWhite

0

We note the sequence goes up in steps of '8'

Hence '8n'.

Next for step #1 4#1 ; n = 1 ; 8(1) + c = 16

8 + c = 16

c = 8

Hence the nth terms is 8n + 8

Verifications

When n = 3 ; 8(3) + 8 = 24 + 8 = 32 ( which is true).

User Avatar

lenpollock

Lvl 16
4mo ago

What else can I help you with?

Related Questions

What is the nth term if the sequence is 32 28 24?

The nth term is (36 - 4n)


What is the nth term for 2 4 8 16 32?

2n


What is the nth term for 248163264?

If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128


What is the nth term of 2 4 8 16 32?

[object Object]


What is the nth term for the sequence 8 16 32 64 128?

The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.


1 2 4 8 16 32 Nth term?

the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.


What is the nth term of 128 64 32 16.?

The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.


What is the nth term of 2 12 22 23?

If you meant: 2 12 22 32 then the nth term = 10n-8


What are the first four terms of a sequence and what term number is -32 when the nth term is 8 -2n?

If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number


How do you find sequence if nth term is 32-5n?

37


What will be the 12th and 77th terms in the series 10 12 14 16?

It appears that the nth term is (8 + 2n).- For n=12, (8 + 2n) = (8 + 24) = 32 .- For n=77, (8 + 2n) = (8 + 154) = 162.


What is the nth term of the geometric sequence 4 8 16 32 ...?

The given sequence is a geometric sequence where each term is multiplied by 2 to get the next term. The first term (a) is 4, and the common ratio (r) is 2. The nth term of a geometric sequence can be found using the formula ( a_n = a \cdot r^{(n-1)} ). Therefore, the nth term of this sequence is ( 4 \cdot 2^{(n-1)} ).