I assume you mean if the minimum measurable is minute, and if something is only measurable to a minute it will round to the nearest minute. Therefore 1 second will be 0 minutes, not 1.
-1
y = -9
The only way that this could happen if enough of the data points have the same value at the minimum. The median is the middle number in a set of data points.So for example: {2,2,2,3,4}. The middle number is 2, which is also the minimum value.
Since the range of the cosine function is (-1,1), the function y = cos(x) assumes a minimum value of -1 for y.
The answer is 1, whatever the value of a.
5 7
any measurable quantity
program for finding a minimum value in javaprogram for finding a minimum value in java
The vertex has a minimum value of (-4, -11)
y=2x2+5. Plug in 0 for x, and you get y=2(0)^2 +5 =0+5=5. 5 is the minimum value for y.
sorry I mean equals x
First take the derivative: y' = 4x - 7 Now, solve for derivate equals zero: 4x - 7 = 0 4x = 7 x = 7/4 Locations where the derivative is zero may be a minimum, or a maximum, or neither (in this case it is indeed a minimum). Finally calculate the value of y for this particular value of x.